我使用下面的这些功能来截取用户屏幕的屏幕截图,并将此屏幕截图与资源中的图像 bmpTest 进行比较。如果找到与 bmpTest 兼容的内容,则返回它的位置。
我的问题是:使用此算法有点慢,需要 10-15秒来解释图像并给出结果。你们中的任何人都知道其他同样但速度更快的方法吗?也许,有一些相似性?我无法在互联网上找到。
private Bitmap Screenshot()
{
// this is where we will store a snapshot of the screen
Bitmap bmpScreenshot = new Bitmap(Screen.PrimaryScreen.Bounds.Width, Screen.PrimaryScreen.Bounds.Height);
// creates a graphics object so we can draw the screen in the bitmap (bmpScreenshot)
Graphics g = Graphics.FromImage(bmpScreenshot);
// copy from screen into the bitmap we created
g.CopyFromScreen(0, 0, 0, 0, Screen.PrimaryScreen.Bounds.Size);
//g.CopyFromScreen(205, 179, 660, 241, new Size(455, 62));
// return the screenshot
return bmpScreenshot;
}
private bool FindBitmap(Bitmap bmpNeedle, Bitmap bmpHaystack, out Point location)
{
for (int outerX = 0; outerX < bmpHaystack.Width - bmpNeedle.Width; outerX++)
{
for (int outerY = 0; outerY < bmpHaystack.Height - bmpNeedle.Height; outerY++)
{
for (int innerX = 0; innerX < bmpNeedle.Width; innerX++)
{
for (int innerY = 0; innerY < bmpNeedle.Height; innerY++)
{
Color cNeedle = bmpNeedle.GetPixel(innerX, innerY);
Color cHaystack = bmpHaystack.GetPixel(innerX + outerX, innerY + outerY);
if (cNeedle.R != cHaystack.R || cNeedle.G != cHaystack.G || cNeedle.B != cHaystack.B)
{
goto notFound;
}
}
}
location = new Point(outerX, outerY);
return true;
notFound:
continue;
}
}
location = Point.Empty;
return false;
}
private void button8_Click_1(object sender, EventArgs e)
{
// takes a snapshot of the screen
Bitmap bmpScreenshot = Screenshot();
// find the login button and check if it exists
Point location;
bool success = FindBitmap(Properties.Resources.bmpTest, bmpScreenshot, out location);
// check if it found the bitmap
if (success == false)
{
MessageBox.Show("Not Found");
return;
}
else
{
MessageBox.Show("Image Found");
}
}
答案 0 :(得分:0)
这是因为位图对象上的每个“GetPixel”调用都会执行锁定,从而导致性能问题。
你可以通过自己处理锁来获得更好的性能,这样你就可以锁定整个位图一次,在你的情况下都是两个位图,然后迭代它的像素。