Question

我想使用gnuplot在同一个窗口上一个接一个地绘制一系列图像。图像具有完全相同的大小，我有许多按顺序称为test_0X.gnu，并且采用gnuplot格式。

我是用bash写的。

ctrl+z

seq -f确保在数字之前存在正确数量的填充零。

这有效，但是一旦脚本启动，我无法阻止它，因为public void getDrawingBitmap() throws Exception{ LinearLayout tabLayout = (LinearLayout)findViewById(R.id.screen_shot_layout); if (tabLayout != null) { Bitmap image = Bitmap.createBitmap(tabLayout.getWidth(), tabLayout.getHeight(), Config.ARGB_8888); Canvas b = new Canvas(image); tabLayout.draw(b); if (image!=null) { // here is your sceenshot }else{ Toast.makeText(DashBord.this, "Unabel to take screen shot", Toast.LENGTH_LONG).show(); } } }或{{1}}不起作用，并且由于不断出现pdf窗口，我无法访问其他终端。 / p>

如何阻止此事？
如何跳过序列（例如10），只显示test_000010.gnu，test_000020.gnu，..等。
奖励：欢迎任何其他更明智的方式。

Answer 1

只需写一个简短的gnuplot脚本

console.log("content script!")

function getIconSpanIfExists() {
    var spanClassName = "imagePoi";
    var matchingElements = document.getElementsByClassName(spanClassName);
    if (matchingElements.length > 1) {
        console.error(failureMessage("wasn't expecting more than one element with class name " + spanClassName));
        return null;
    }

    if (matchingElements.length === 0) {
        return null;
    }

    return matchingElements[0].parentNode;
}

function htmlReady() {
    return getIconSpanIfExists();
}

function addIcons() {
    var iconSpan = getIconSpanIfExists();

    // Append into body - works.
//    var icon = document.createElement("img");
//    icon.id = "seenIcon";
//    icon.src = chrome.extension.getURL("seen.png");
//    document.body.appendChild(icon);
//    console.log("appended " + icon.id + " into body");

    // Append into span - doesn't work, even though it says childNodes.length is 2.
    var icon = document.createElement("img");
    icon.id = "seenIcon";
    icon.src = chrome.extension.getURL("seen.png");
    icon.style.left = "200px";
    icon.style.top = "200px";
    iconSpan.appendChild(icon);
    console.log("appended " + icon.id + " into span with class imagePoi" + " new children: " + iconSpan.childNodes.length);

    // Modify innerHTML of span - doesn't work, even though innerHTML has the icon.
//    iconSpan.innerHTML += "\n<img id=\"seenIcon\""
//        + "src=\"" + chrome.extension.getURL("seen.png") + "\""
//        + "style=\"left: 200px; top: 200px;\">";
//    console.log(iconSpan.parentNode.id, iconSpan.innerHTML);
}

function init() {
    console.log("initialising content script");

    if (!htmlReady()) {
        console.log("not all HTML is loaded yet; waiting");

        var timer = setInterval(waitForHtml, 200);

        function waitForHtml() {
            console.log("waiting for required HTML elements...");
            if (htmlReady()) {
                clearInterval(timer);
                console.log("... found them!");
                addIcons();
            }
        }

        return;
    }
}

if (document.readyState === "complete") {
    console.log("document is complete")
    init();
} else {
    console.log("document is not yet ready; adding listener")
    window.addEventListener("load", init, false);
}

并运行此

Answer 2

gnuplots“gif”终端可以制作现成的动画。

skip=5 # change as needed
set term gif animate 10 # 10/100 s delay between frames
set out "test.gif"
# assuming your data files are named "test_0001.dat" etc.
do for [i=1:100:skip] {plot sprintf("test_%04.f.dat",i)}
set out

bash / gnuplot脚本，用于生成类似电影的效果

2 个答案: