Question

成功返回时的登录API：

{"status":0,"data":{userid:1,username:"abc"},"msg":"login sucess"}

但是当错误服务器返回时：

{"status":0,"data":[],"msg":"login failure！"}

如何定义对象，然后使用gson解析数据字段！感谢。

Answer 1

是 json 还是 gson ？例如，您的回复是针对此变量$response;

您可以尝试：

<?php
$response = '{"status":0,"data":{userid:1,username:"abc"},"msg":"login sucess"}';

// $response = '{"status":0,"data":[],"msg":"login failure！"}';

$response = json_decode($response);
if(empty($response->data){
    echo $response->msg;
}

// print_r($response); //you can try to print_r $response here
// if have data to login, do what you want

使用gson解析jsonarray和jsonobject

1 个答案: