SQL SUMPRODUCT有一个扭曲

时间:2015-07-25 02:15:27

标签: mysql sql

Table WIDGET
    Columns Country, Contract, Price

Table WEIGHT
    Columns Contract, Weight

我正在尝试SUMRPRODUCT(Contract, Weight)/SUM(Weight)Country的所有值。我尝试过的内容改编自Weighted average in T-SQL (like Excel's SUMPRODUCT),看起来像

SELECT 
    Country 
    SUM(widget.price * weight.weight) / SUM(weight.weight)
FROM
    Widget
        INNER JOIN
    Weight ON Widget.contract = Weight.contract
WHERE
    Weight.contract >= '2016-01-01'
    AND Weight.contract <= '2016-12-01'

这个问题在于它计算了Country的一个值,但并非所有值都计算出来。如何获取旁边已过滤合约的DISTINCT(Country)SUMPRODUCT()/SUM()列表?

样本数据

+-----------+---------+------------+-------+
| widget_id | country | contract   | price |
+-----------+---------+------------+-------+
|         4 | CA      | 2016-01-01 | 16.00 |
|         5 | CA      | 2016-02-01 | 32.00 |
|         6 | CA      | 2016-03-01 | 64.00 |
|         1 | US      | 2016-01-01 | 32.00 |
|         2 | US      | 2016-02-01 | 64.00 |
|         3 | US      | 2016-03-01 | 96.00 |
+-----------+---------+------------+-------+

+-----------+------------+--------+
| weight_id | contract   | weight |
+-----------+------------+--------+
|         1 | 2016-01-01 |      1 |
|         2 | 2016-02-01 |      8 |
|         3 | 2016-03-01 |     64 |
+-----------+------------+--------+

期望的输出

+---------+-----------+
| Country | Wtd Price |
+---------+-----------+
| CA      | 59.835616 |
| US      | 91.616438 |
+---------+-----------+

1 个答案:

答案 0 :(得分:2)

你应该按国家分组

SELECT 
    Country 
    SUM(widget.price * weight.weight) / SUM(weight.weight)
FROM
    Widget
        INNER JOIN
    Weight ON Widget.contract = Weight.contract
WHERE
    Weight.contract >= '2016-01-01'
    AND Weight.contract <= '2016-12-01'
GROUP BY Country