Question

对于一个学校项目，我一直在制作一个游戏，允许用户猜测足球比赛的最终结果，并能够在那里下注预测。如果他们的余额小于或等于零但我无法这样做，我一直试图打破while循环。整个Python代码比下面显示的要广泛得多，但这是唯一的问题。

tries = int(input("How many attempts would you like : "))

while balance > tries:
   while guesses < 2:

        print ("\nYour current balance is : £",balance)

        gameresultguess = input("\nWho will win - Home, Away, or Draw : ")
        bettingchoice = input("Would you like to bet this round - Yes or No : ")

        while True:
            if str.lower(bettingchoice) == "yes":
                bet = int(input("How much would you like to bet : "))
            if bet > balance: break
            print ("You have insuficient funds to bet this much, please try again")

        guesses +=1

        hometrue = random.randint(1,7)
        awaytrue = random.randint(1,5)

        if hometrue > awaytrue:
             gameresulttrue = "home"

        if awaytrue > hometrue:
             gameresulttrue = "away"

        if hometrue == awaytrue:
             gameresulttrue = "draw"

        if str.lower(gameresultguess) == gameresulttrue:
             print ("Correct! Nice guess! The final score was ",hometrue," : ",awaytrue)
             if str.lower(bettingchoice) == "yes":
                  balance = (balance + bet)
                  print ("Well played! Your bet has been doubled and added to your balance")
             if str.lower(bettingchoice) == "no":
                  print ("Unlucky... Should have placed a bet")

        else:
             print ("Unlucky! The final score was : ",hometrue," : ",awaytrue)
             if str.lower(bettingchoice) == "yes":
                  balance = (balance - bet)
                  print ("Oops... Better luck next time")

print ("Ouch... You went bankrupt. Try coming back when you have more money")

Answer 1

当你打电话给休息时，它会突破你当前的循环。

while True:
    if str.lower(bettingchoice) == "yes":
        bet = int(input("How much would you like to bet : "))
    if bet > balance: break
    print ("You have insuficient funds to bet this much, please try again")

在你的例子中，我相信你指的是平衡低于赌注的循环，你试图结束游戏？

为此，您可以将此逻辑转换为函数并返回＆＃34;结果＆＃34;赌注。或者，如果您希望保留当前结构，则可以引发异常并捕获以打印最终的＆＃34;破产＆＃34;消息。

class InsufficientFundError(Exception): pass

try:
    while balance > tries:
        while guesses < 2:
            ...
            while True:
                ...
                if bet > balance:
                    raise InsufficientFundError()
except InsufficientFundError:
    print("Ouch... You went bankrupt. Try coming back when you have more money")

Answer 2

＆＃34;我一直试图打破while循环，如果他们的余额小于或等于零但是无法这样做。＆＃34;

如果余额小于或等于零，你试图打破哪个while循环？我假设＆＃34;最大＆＃34;你发布的一个，因为人们可以继续用负余额进行投注是没有意义的。

为此，您必须将其设置为初始条件。尝试：

// Ajax Success function
$.playSound('../static/sounds/cash-register', 'next_page');

// Play sound function
(function($){

    $.extend({
        playSound: function(){
            var $ele = $("<embed src='"+arguments[0]+".mp3' hidden='true' autostart='true' loop='false' class='playSound'>" + "<audio autoplay='autoplay' style='display:none;' controls='controls'><source src='"+arguments[0]+".mp3' /><source src='"+arguments[0]+".ogg' /></audio>").appendTo('body');
            $ele.on('ended', function() {
                window.location.replace(arguments[1]);
            });
        }
    });

})(jQuery);

通过此，您的投注流程＆＃34;当用户达到负余额或资金不足时，嵌套在此循环下的将停止。

Answer 3

感谢您的帮助!!

在看完答案之后，我看到这只是我错误地提前打破了陈述。对不起，问题就在这了。

再次感谢：）

如果Python中的变量小于或等于零，则结束while循环

3 个答案: