Question

我试图从名为＆＃34; post_id的数据库中获取属性的值，以便在其他地方使用。

这是我的型号代码。

$copy_query = "SELECT post_id FROM posts order by post_id DESC limit 1"; //query for selecting last post's post_id
$result = $this->db->query($copy_query);    //adding that post_id to the $result variable 

$sub_data = array(
                    'study_education_level' => $this->input->post('sub_education_level'),
                    'tourism_country' => $this->input->post('sub_tourism_country'),
                    'tourism_place_name' => $this->input->post('sub_tourism_placeName'),
                    'post_id' => $result
            );

            $this->db->insert('subcategories',$sub_data);

但每当我运行代码时，它都会给我两个ERROR。

遇到PHP错误

Severity: 4096

Message: Object of class CI_DB_mysql_result could not be converted to string

Filename: mysql/mysql_driver.php

Line Number: 553

和 2.

A Database Error Occurred

Error Number: 1064

You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ')' at line 1

INSERT INTO `subcategories` (`study_education_level`, `tourism_country`, `tourism_place_name`, `post_id`) VALUES ('Higher Study', '', '', )

Filename: C:\xampp\htdocs\learn\system\database\DB_driver.php

Line Number: 331

先谢谢你！

Answer 1

顺便说一下我解决了问题:)

$result = $this->db->query($copy_query);    //adding that post_id to the variable   
            if ($result->num_rows() > 0)
            {
                    foreach ($result->result() as $row)
                    {
                            $post_id_plz =  $row->post_id;
                    }
            }

Codeigniter，Database Errror，严重性：4096消息：类CI_DB_mysql_result的对象无法转换为字符串

1 个答案: