Question

尝试将输出写入csv并获取缩进错误。我确定这是一个愚蠢的错误，但我无法弄清楚它为什么被抛出。

#!/usr/bin/env python

import csv
import copy
import os
import sys
import glob

#get current working dir, set count, and select file delimiter
os.chdir('/Users/Briana/Documents/Misc./PythonTest')

#parses through files and saves to a dict
series = {}
for fn in glob.glob('*.txt'):
    with open(fn) as f:
        series[fn] = (1 for line in f if line.strip() and not line.startswith('#')) 

print series

#save the dictionary with key/val pairs to a csv
with open('seriescount.csv', 'wb') as f: 
    w = csv.DictWriter(f, series.keys()) #error thrown here
    w.writeheader()
    w.writerow(sum(names.values()))

完整追溯：

Fri Jul 24 03:13 PM [Briana PythonTest] (dev) $ ./SeriesCount.py 
File "./SeriesCount.py", line 22 
    w = csv.DictWriter(f, series.keys()) 
                                       ^ 
    IndentationError: expected an indented block

Answer 1

如果您在此处完全提交了代码，那么空格和标签就会混合在一起。如果我复制你问题中出现的代码，它会一致地缩进，带有空格;但是，如果我按“编辑”然后检查代码，前21行用空格缩进，第22-24行用缩进键缩进。下面的代码修复了这个错误;注意完全按照此处显示的方式进行复制：

#!/usr/bin/env python

import csv
import copy
import os
import sys
import glob

#get current working dir, set count, and select file delimiter
os.chdir('/Users/Briana/Documents/Misc./PythonTest')

#parses through files and saves to a dict
series = {}
for fn in glob.glob('*.txt'):
    with open(fn) as f:
        series[fn] = (1 for line in f if line.strip() and not line.startswith('#')) 

print series

#save the dictionary with key/val pairs to a csv
with open('seriescount.csv', 'wb') as f:
    w = csv.DictWriter(f, series.keys()) #error thrown here
    w.writeheader()
    w.writerow(sum(names.values()))

IndentationError: expected an indented block有三个常见原因：

忽略或忘记缩进
评论缩进块的一部分
在缩进中混合制表符和空格

Python Dict to CSV：预期缩进块

1 个答案: