Question

我有两张桌子，巡回赛表和旅游日期表。

参观表
- 编号
- tour_title

这是表格的链接tour table！

tour_dates表
- ID
- tour_id
- 价

这是表格的链接tour_date table！

现在我正在使用价格区间的过滤器，如

从$ 10到$ 50
从$ 50到$ 80
从$ 80到$ 100

我尝试过很多不同的连接查询，甚至尝试过像这样的嵌套查询。

$qry = "SELECT * FROM `tours` WHERE status='1' ";
$qry1 = mysqli_query($con,$qry);
while($data = mysqli_fetch_array($qry1)){

$qfilter = "SELECT * FROM `tour_dates` WHERE tour_id='".$data['id']."' AND (`price` BETWEEN 10 AND 50) ORDER BY price DESC ";
    $qfilter1 = mysqli_query($con,$qfilter);
    $tour_ob = mysqli_fetch_object($qfilter1);
    $num = mysqli_num_rows($qfilter1);
    if($num>0){ 
     ------
      }
    }

请提供任何解决方案。谢谢。

Answer 1

您可以使用联接从两个表中获取数据。

select t1.id,t1.tour_title,t2.price  
from tours t1 inner join tour_dates t2 on t1.id=t2.tour_id 
where t1.id=tour_id and (t2.price between 10 and 50) order by t2.price desc

您可以编写存储过程来处理动态的条件。

CREATE PROCEDURE `procedure_name` (in in_condition varchar(1000))
BEGIN
      set @query='select t1.id,t1.tour_title,t2.price  
                  from tours t1 inner join tour_dates t2 on t1.id=t2.tour_id 
                  where t1.id=tour_id ';

       set @query=concat(@query,' and ',in_condition,' order by t2.price desc');

        prepare stmt from @query;
        execute stmt;
        deallocate prepare stmt;
END

使用Range从两个表中获取数据

1 个答案: