Question

var myApp = angular.module("myApp", ['ngResource']);

myApp.factory("server", function($resource) {

  return $resource('https://tcp.firebaseio.com/graph.json')

})

myApp.controller("main", function($scope, server) {

  $scope.test = "Hellow";

  $scope.data = server.query();

  $scope.data.$promise.then(function(result) {

    $scope.values = result;
    $scope.defaultValue = $scope.values[0].value;

    console.log($scope.defaultValue);

  })

  $scope.updateGraph = function(item) {

    $scope.defaultValue = item.value;

  }

});


var planVsActual = function($timeout) {

  return {

    replace: true,

    template: "<div id='pieGraph'></div>",

    link: function(scope, element, attr) {

      $timeout(function() {

        scope.$watch("defaultValue", function(newVal, oldVal) {

          var phraseValue = [newVal, 100 - newVal];
          drawPie(phraseValue);

          function drawPie(array) {

            console.log(element.width)

            var width = element.width(), height = element.height(),
                    radius = Math.min(width, height) / 1.2, data = array;

              if (!array.length) return;

              var color = d3.scale.ordinal()
                    .domain(array) 
                    .range(["#ffff00", "#1ebfc5"]);

                    var pie = d3.layout.pie()
                    .sort(null)
                    .value(function(d) { return d });

                    var arc = d3.svg.arc()
                      .outerRadius(radius - 90)
                      .innerRadius(radius - 85);

                      var svg = d3.select("#pieGraph")
                      .append("svg")
                    .attr("width", width)
                    .attr("height", height)
                    .append("g")
                    .attr("transform", "translate(" + width / 2 + "," + height / 2 + ")");

                    var g = svg.selectAll(".arc")
                      .data(pie(array))
                        .enter().append("g")
                        .attr("class", "arc");

                    g.append("path")
                      .attr("d", arc)
                      .style("fill", function(d,i) {  return color(d.data); });

                      g.append("text")
                     .text(array[0]+'%')
                     .attr("class", "designVal")
                     .style("text-anchor", "middle")


          }

        })

      }, 100)


    }

  }

}

angular.module("myApp")

.directive("planVsActual", planVsActual);

我是hive的新手，我也不擅长sql。我试图运行多连接查询，但我不断收到此错误：

SELECT t.col1, t.col2, t.col3, e.col1
FROM table1 t
JOIN table2 s
ON (t.col1 = s.col1) sv
JOIN table3 e
ON (sv.col1 = e.col1) svv
JOIN table4 c
ON (svv.col3 = c.col3);

Answer 1

删除别名＆＃39; sv＆＃39; svv＆＃39;。我不确定你尝试做什么，但你已经为你的桌子设置了别名字符＆＃39;＆＃39; e＆＃39;并且＆＃39; c＆＃39;。我给你的建议是：使用具体的标识符作为别名和你在这里做的连接，你会很快失去焦点。

我假设您要执行以下操作：

SELECT t1.col1, t1.col2, t1.col3, t3.col1
FROM table1 t1
JOIN table2 t2
ON (t1.col1 = t2.col1)
JOIN table3 t3
ON (t2.col1 = t3.col1) 
JOIN table4 t4
ON (t3.col3 = t4.col3);

配置单元中的多连接查询

1 个答案: