更新:我使用PHP BLOB上传了图像,但它们没有显示在mysql表中。图像正在移动到目标文件夹,但未显示在表格中。当我获取图像时,此代码无法显示
上传图片的代码
<?php
if (isset($_POST['add_p'])) {
@$pn = $_POST['pname'];
@$pp = $_POST['pprice'];
@$pc = $_POST['pcategory'];
@$date = date('d-m-y H:i:s');
$img = $_FILES['img']['name'];
$tmp_img = $_FILES['img']['tmp_name'];
move_uploaded_file($tmp_img, "uploads/$img");
$insert = "INSERT INTO products (`p_name`, `p_price`, `img`, `p_category`, `date_added`) VALUES ('$pn', '$pp', '$img', '$pc', '$date')";
mysqli_query($con, $insert);
}
?>
<form action="add-product.php" method="POST" class="form">
Name: <input class="inpt" type="text" name="pname">
Price: <input class="inpt" type="text" name="pprice">
Upload Image: <input class="inpt" type="file" name="img">
Select Category
<select class="inpt" name="pcategory">
<option>Men</option>
<option>Women</option>
<option>Kids</option>
</select>
<input type="submit" name="add_p" value="Add Product">
</form>
获取图像的代码
<?php
$get = "SELECT * FROM products ORDER BY p_id DESC LIMIT 0,4";
$query = mysqli_query($con, $get);
while ($row = mysqli_fetch_array($query)) {
echo $id = $row['p_id'];
echo $n = $row['p_name'];
echo $p = $row['p_price'];
echo $c = $row['p_category'];
echo $i = $row['img'];
}
?>
答案 0 :(得分:1)
在表单中添加enctype='multipart/form-data'
以支持文件上传:
<form action="add-product.php" method="POST" class="form" enctype="multipart/form-data">
See this answer了解有关HTML表单编码类型的更多详细信息。