Question

欢迎，

我有两张表int_client和int_client_bank。

在第一个重要栏目中：client_id, firstname, lastname, country, email, status。在第二个：client_id, status。

我需要显示第一列的所有记录：firstname, lastname, country, e-mail WHERE status='25'（第二个表中出现client_id的记录除外）。如果第二个表中出现client_id，则跳过第一列的状态，并在secound表中仅显示status='25'。

Sb可以帮助我吗？

编辑：

SELECT firstname, lastname, country, email, COALESCE(b.status, a.status) status
 FROM int_client a
 LEFT JOIN int_client_back b USING (client_id)
 WHERE 
  (b.status IS NULL and a.status='25')
  OR b.status IS NOT NULL;

这是一个很好的代码，但我只需要显示有状态=＆＃39; 25＆＃39;在B列中，如果a.client_id！= b.client_id，我需要显示记录，其状态为=＆＃39; 25＆＃39;在A栏

某人，帮帮忙？

Answer 1

带有LEFT JOIN的

COALESCE()应该：

SELECT firstname, lastname, country, email, COALESCE(b.status, a.status) status
 FROM int_client a
 LEFT JOIN int_client_back b USING (client_id)
 WHERE 
  (b.status IS NULL and a.status='25')
  OR b.status IS NOT NULL;

Answer 2

此选择查询应该有效：

SELECT t1.first_name,t1.last_name,t1.country,t1.email FROM int_client AS t1, int_client_bank AS t2
WHERE t1.client_id = t2.client_id AND t1.status = 25;

Answer 3

以下是为您提供帮助的查询。

SELECT client_id, firstname, lastname, country, email, status FROM int_client as ic LEFT JOIN int_client_back icb ON ic.client_id=icb.client_id WHERE ic.status=25

Answer 4

如果我理解正确，您需要来自int_client的所有记录，状态为＆＃34; 25＆＃34;。但是，如果int_client_bank中存在其他状态，则您希望显示该状态。

select c.first_name, c.last_name, c.email, c.country,
       coalesce(cb.status, c.status)
from int_client c left join
     int_client_bank cb
     on cb.client_id = c.client_id
where c.status = 25;

Answer 5

SELECT DISTINCT firstname, lastname, country, email, 
a.status as status_a, b.status as status_b, if(b.status is NULL, a.status, b.status) as final_status
 FROM int_client a
 LEFT JOIN int_client_bank b USING (client_id)
 WHERE 
  if(b.status is NULL, a.status, b.status) = '25'

Sql离开了联接并显示结果

5 个答案: