Question

我有一个大问题，我们正在努力在项目中实施单曲。我们的管理员在DB（FEDERATED）中创建了一些表mysql，因为这个应用程序抛出了很多异常。如何在JPA中将ManyToOne关联的字段映射到该联合表？它在更新时抛出异常，并在列LOCALITY_ID的表用户中插入（它必须只有id）。

错误：

javax.persistence.PersistenceException：org.hibernate.PropertyValueException：not-null属性引用null或transient值：...... stuff

public class User extends BaseEntity implements IAccessDataAware, UserDetails, IAuditable {

    /** serial version */
    private static final long serialVersionUID = 2899839338023778586L;

    @Embedded
    private AccessData accessData = new AccessData();

    @Column(name = "FIRST_NAME", length = Constants.COLUMN_NORMAL_LENGTH, nullable = false)
    private String firstName;

    @Column(name = "LAST_NAME", length = Constants.COLUMN_NORMAL_LENGTH, nullable = false)
    private String lastName;

    @Column(name = "CNP", length = Constants.COLUMN_CNP_LENGTH, nullable = true)
    private String cnp;

    @Column(name = "EMAIL", length = Constants.COLUMN_NORMAL_LENGTH, nullable = false)
    private String email;

    @Column(name = "PHONE", length = Constants.COLUMN_NORMAL_LENGTH)
    private String phone;

    @Column(name = "USERNAME", length = Constants.COLUMN_NORMAL_LENGTH, nullable = false)
    private String userName;

    @Column(name = "PASSWORD", length = Constants.COLUMN_MD5_ENCRYPTED_LENGTH, nullable = false)
    private String password;

    @Column(name = "PASSWORD_OAUTH", length = Constants.COLUMN_ENCRYPTED_LENGTH, nullable = true)
    private String passwordOAuth;

    @Column(name = "SALT_OAUTH", length = Constants.COLUMN_ENCRYPTED_LENGTH, nullable = true)
    private String salt;

    @Column(name = "PASSWORD_OAUTH_ALGORITHM", length = Constants.COLUMN_ENCRYPTED_LENGTH, nullable = true)
    private String passwordOAuthAlgorithm;

    @Column(name="digital_signature")
    private Boolean digitalSignature=Boolean.FALSE;

    @Column(name = "DESCRIPTION", length = Constants.COLUMN_DESCRIPTION_LENGTH)
    private String description;

    @Column(name = "PATH_AVATAR_IMAGE", length = Constants.COLUMN_NORMAL_LENGTH)
    private String pathAvatarImage;

    @Column(name = "PATH_AVATAR_IMAGE_ORIGINAL", length = Constants.COLUMN_NORMAL_LENGTH)
    private String pathAvatarImageOriginal;

    @ManyToOne(optional = false)
    @JoinColumn(name = "ROLE_ID")
    private Role role;

    @OneToMany(mappedBy = "user")
    private List<HistoryEvent> historyEvents;

    @ManyToOne(cascade = {CascadeType.ALL})
    @JoinColumn(name = "LOCALITY_ID")
    private Locality locality;


....... Getters and Setters


}

谢谢

JPA使用JoinColumn映射ManyToOne而不是FEDERATED mysql表

0 个答案: