Question

使用php（autent.php）中的这些代码说明，我认为一切都很好但是当我登录时，我收到错误：

解析错误：语法错误，第30行中文件autent.php的意外结束

完成php指令后的最后一行是＃34; ？＆GT; ＆＃34;

<?php
include "connect.php";
/*connect to database with oracle 11g*/

$email = $_GET['username'];
$passw = $_GET['password'];

$query   = "SELECT * login WHERE user_email = '$email' AND user_pass= '$passw'";
$sid     = oci_parse($conn, $query);
$result  = oci_execute($sid);
$dbarray = oci_fetch_array($sid);


if (($email != "") && ($passw != "")) {
    if ($dbarray["user_email"] != $email) {
        echo "<script> alert('Wrong Email!'); history.back() </script>";
        exit;
    }
    if ($dbarray["user_pass"] != $passw) {
        echo "<script> alert('Wrong Password!'); history.back() </script>";
        exit;
    }
    if (($dbarray["user_email"] == $email) && ($dbarray["user_pass"] == $passw)) {
        session_start();
        $_SESSION["user_email"] = $email;
        $_SESSION["user_pass"]  = $passw;
        switch ($dbarray["type_user_id"]) {
            case 1:
                header("Location: admin.php");
                break;
            default:
                echo "<script> alert('ERROR:'); history.back() </script>";
                exit;
                break;
        }
    } else {
        echo "<script> alert('ERROR:'); history.back() </script>";
        exit;
    }

?>

Answer 1

你遗漏了FROM

$query = "SELECT * login WHERE user_email = '$email' AND user_pass= '$passw'";

正确的是

$query = "SELECT * FROM login WHERE user_email = '$email' AND user_pass= '$passw'";

你也错过了这里的右括号

    }
} else {
    echo "<script> alert('ERROR:'); history.back() </script>";
    exit;
}

?>

所以正确

if (($email != "") && ($passw != "")) {
        if ($dbarray["user_email"] != $email) {
            echo "<script> alert('Wrong Email!'); history.back() </script>";
            exit;
        }
        if ($dbarray["user_pass"] != $passw) {
            echo "<script> alert('Wrong Password!'); history.back() </script>";
            exit;
        }
        if (($dbarray["user_email"] == $email) && ($dbarray["user_pass"] == $passw)) {
            session_start();
            $_SESSION["user_email"] = $email;
            $_SESSION["user_pass"]  = $passw;
            switch ($dbarray["type_user_id"]) {
                case 1:
                    header("Location: admin.php");
                    break;
                default:
                    echo "<script> alert('ERROR:'); history.back() </script>";
                    exit;
                    break;
            }
        }
} else {
        echo "<script> alert('ERROR:'); history.back() </script>";
        exit;
    }

PHP - 解析错误：语法错误，意外的文件结束

1 个答案: