我需要弄清楚如何将基于注释的过滤应用于定义为的枚举参数列表:
@Column(name = "target_status")
@Enumerated(EnumType.STRING)
@Type(type="PGEnumConverter", parameters = {
@Parameter(name = "enumClassName",
value = "com.company.model.campaign.CampaignTarget$Status")
})
private Status targetStatus;
所以我的@FilterDef
看起来像这样:
@FilterDef(name="filterCampaignTargetByStatuses",
defaultCondition="target_status in (:statuses)",
parameters = @ParamDef(name = "statuses", type = "string"))
当我启用过滤器时,它看起来像这样:
session.enableFilter("filterCampaignTargetByStatuses").
setParameterList("statuses", statuses);
我从休眠中得到的错误是:
org.hibernate.HibernateException: Incorrect type for parameter [statuses]
数据在PostgreSQL中以及类型的定义:
CREATE TYPE statuscmp AS ENUM ('ACTIVE','INACTIVE','PAUSED','DRAFT','SCHEDULED','ENDED','ARCHIVED');
我已经看到很多关于如何针对单个Enum值执行条件查询和过滤的SO问题,但还没有关于过滤Enum值的集的问题。有没有办法明确地转换个别值?
答案 0 :(得分:0)
您不必一般“强制转换”该值,实际上您只需要以它们存储的形式传递值。
如果我们假设您的字段仅注释为@Enumerated(EnumType.STRING)
,则该列将是纯varchar字段。
(将java类型映射到postgres枚举是另一个重要主题。)
如果您现在想要将Status
枚举实例的列表与数据库中的相关字符串值进行比较,请将其作为字符串集合传递,换句话说,如果是toString()
方法,请将其称为enum
方法java public enum EntityStatus {
A, B, C;
}
。
E.g。这是你的枚举:
import javax.persistence.Entity;
import javax.persistence.EnumType;
import javax.persistence.Enumerated;
import javax.persistence.GeneratedValue;
import javax.persistence.GenerationType;
import javax.persistence.Id;
import org.hibernate.annotations.Filter;
import org.hibernate.annotations.FilterDef;
import org.hibernate.annotations.ParamDef;
@Entity
@FilterDef(name = "byMultipleStates", defaultCondition = "status in (:states)", parameters = @ParamDef(name = "states", type = "string"))
@Filter(name = "byMultipleStates", condition = "status in (:states)")
public class StatusEntity {
@Id
@GeneratedValue(strategy = GenerationType.AUTO)
private long id;
@Enumerated(EnumType.STRING)
private EntityStatus status;
public long getId() {
return id;
}
public EntityStatus getStatus() {
return status;
}
public void setStatus(EntityStatus status) {
this.status = status;
}
}
这是你的实体:
public List<StatusEntity> filterByStates(final Set<EntityStatus> states) {
final Session hibernateSession = entityManager.unwrap(Session.class);
hibernateSession.enableFilter("byMultipleStates").setParameterList("states",
states.stream().map(state -> state.toString()).collect(Collectors.toList()));
final Query query = hibernateSession.createQuery("SELECT e FROM StatusEntity e");
return query.list();
}
这可能是您要过滤的代码:
public List<StatusEntity> filterByStates(final Set<EntityStatus> states) {
final Set<String> statesAsString = new HashSet<>();
for (final EntityStatus state : states) {
statesAsString.add(state.toString());
}
final Session hibernateSession = entityManager.unwrap(Session.class);
hibernateSession.enableFilter("byMultipleStates").setParameterList("states", statesAsString);
final Query query = hibernateSession.createQuery("SELECT e FROM StatusEntity e");
return query.list();
}
或者在Java 8之前的方式:
app.get('*', function (request, response, next) {
let app = request.cookies.app;
if (app) {
response.sendFile(path.resolve(__dirname, 'app.html'))
} else {
response.sendFile(path.resolve(__dirname, 'app2.html'))
}
});
因此,只需过滤一组值即可。