Question

这是我下面的代码我需要禁用工作日，并且还有几天我该怎么做？有人可以帮助我吗？

$(document).ready(function(){
var Desingndate = $('#DesignIdUnavialble').html();
var splitdate = Desingndate.split(',');
   // console.log(splitdate.length);
    var arrDisabledDates = {};
    for (var i = 0; i < splitdate.length; i++) {
        //console.log(splitdate[i]);    
    arrDisabledDates[new Date(splitdate[i])] = new Date(splitdate[i]);    
    }

     $("#iDate").datepicker({       
        dateFormat: 'dd-mm-yy',
        beforeShowDay: function (dt) {
            var bDisable = arrDisabledDates[dt];
            if (bDisable) return [false, '', ''];
            else return [true, '', ''];
        }
    });

});

Answer 1

查看here

我修改了你的else语句以禁用所有工作日：

var bDisable = arrDisabledDates[dt];
if (bDisable) return [false, '', ''];
else {
    return [dt.getDay() == 6 || dt.getDay() == 0,""];
}

Answer 2

Working Fiddle

这可能对您有所帮助

function deadlinedates(date) {
      dmy = date.getDate() + "-" + (date.getMonth()+1) + "-" + date.getFullYear();
      var day = date.getDay();

        var Desingndate = $('#DesignIdUnavialble').html();
        var splitdate = Desingndate.split(','); 
        var arrDisabledDates = {};
        for (var i = 0; i < splitdate.length; i++) {        
        arrDisabledDates[new Date(splitdate[i])] = new Date(splitdate[i]);    
        }

       var bDisable = arrDisabledDates[date];
       if (bDisable) return [false, '', ''];
       else return [(day != 0 && day != 6)];

    }


$(document).ready(function(){

     $("#iDate").datepicker({       
        dateFormat: 'dd-mm-yy',
        beforeShowDay: deadlinedates
    });

});

如何在jquery datepicker中禁用工作日和自定义日期？

2 个答案: