Question

我有一个对象A.

如果我JSON.stringify(A)，我得到这个结果：

{
    "OrderA": [{
        "orderId": "19",
        "serverId": 129,
        "description": "Apple",
        "status": "1",
        "details": ""
    }]
}

现在，我想克隆它自己的元素并创建一个更大的对象：

{
    "OrderA": [{
        "orderId": "19",
        "serverId": 129,
        "description": "Apple",
        "status": "1",
        "details": ""
    }],
    "OrderA": [{
        "orderId": "19",
        "serverId": 129,
        "description": "Apple",
        "status": "1",
        "details": ""
    }],
     "OrderA": [{
        "orderId": "19",
        "serverId": 129,
        "description": "Apple",
        "status": "1",
        "details": ""
    }]
}

如何使用lodash / underscore /或jQuery实现这一目标？

到目前为止，我已经尝试过jQuery.extend，lodash union，并且没有工作。

Answer 1

您无法创建您描述的对象。您在每种情况下重复属性名称"OrderA"，这是不允许的。我建议使用一个新数组并将对象推入内部，而不是具有属性名称的映射对象。像这样粗糙的东西：

var A; //Your OrderA Object.
var B = jQuery.extend(true, {}, A),
    C = jQuery.extend(true, {}, A),
    D = jQuery.extend(true, {}, A);

var arr = [A, B, C, D];

Answer 2

我认为你需要使用不同的密钥，但这不会起作用吗？

var A = {
    "OrderA": [{
        "orderId": "19",
        "serverId": 129,
        "description": "Apple",
        "status": "1",
        "details": ""
    }]
};

var B = {};

for (var attr in A.OrderA[0]) {
  if (A.OrderA[0].hasOwnProperty(attr)) {
    B[attr] = A.OrderA[0][attr];
  }
}

A.OrderB = [B];

JSON.stringify(A);

{
    "OrderA": [{
        "orderId": "19",
        "serverId": 129,
        "description": "Apple",
        "status": "1",
        "details": ""
    }],
    "OrderB": [{
        "orderId": "19",
        "serverId": 129,
        "description": "Apple",
        "status": "1",
        "details": ""
    }]
}

Answer 3

对象键必须是唯一的，否则您将覆盖以前保存的数据。请参阅DEMO。

以下是：

＆＃13;

var ALL = {
    "OrderA": [{
        "orderId": "19",
        "serverId": 129,
        "description": "Apple",
        "status": "1",
        "details": ""
    }]
};

['B','C','D'].forEach(function(letter,index) {
    ALL['Order'+letter] = $.extend(true, {}, ALL.OrderA);
});

console.log( JSON.stringify( ALL ) );

＆＃13;

<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>

＆＃13;

克隆一个对象的元素并推送它自己

3 个答案: