Question

try
{
    if(ruleName.equalsIgnoreCase("RuleName"))
    {
        cu.accept(new ASTVisitor()
        {
            public boolean visit(MethodInvocation e)
            {
                if(rule.getConditions().verify(e, env, parentKeys, astParser, file, cu)) // throws ParseException
                    matches.add(getLinesPosition(cu, e));
                return true;
            }
        });
    }
    // ...
}
catch(ParseException e)
{
    throw AnotherException();
}
// ...

我需要在底部捕获中捕获抛出的异常，但我不能通过throws构造重载方法。怎么办，请指教？感谢

Answer 1

创建自定义异常，在匿名类中编写try catch块并在catch块中捕获它。

Sensor countSensor = sensorManager.getDefaultSensor(Sensor.TYPE_STEP_COUNTER);
if (countSensor !=null
{
    sensorManager.registerListener(this,CountSensor,SensorManager.SENSOR_DELAY_UI);
} else {
    Toast.makeText(this,"Count Sensor not Availabe in this device !!",Toast.LENGTH_LONG).show();
}

现在

class CustomException extends Exception
{
      //Parameterless Constructor
      public CustomException () {}

      //Constructor that accepts a message
      public CustomException (String message)
      {
         super(message);
      }
 }

Answer 2

正如已经建议的那样，可以使用未经检查的异常。另一种选择是改变最终变量。例如：

final AtomicReference<Exception> exceptionRef = new AtomicReference<>();

SomeInterface anonymous = new SomeInterface() {
    public void doStuff() {
       try {
          doSomethingExceptional();
       } catch (Exception e) {
          exceptionRef.set(e);
       }
    }
};

anonymous.doStuff();

if (exceptionRef.get() != null) {
   throw exceptionRef.get();
}

Java - 如何在异常类之外抛出异常

2 个答案: