Question

好的，这可能类似于这个主题：Finding 4 highest values from an array

但我不知道如何使用2d列表这样做，所以这是我的问题：我有一个清单：

teams = [Randomteam1,Randomteam2,Randomteam3,Randomteam4,Randomteam5,Randomteam6]

和2d列表：

team_info = [[7, 2, 1, 1, 3], [4, 1, 1, 1, 3],[2, 0, 2, 2, 3], [12, 3, 0, 0, 3]],
             [9, 0, 2, 2, 3], [10, 3, 0, 0, 6]]

在该列表中，每个例如，[7,2,1,1,3]是团队得分的信息，7是多少分，2多少胜利，1失败，1抽奖，3是游戏播放。 team_info中的每个块都与团队中的一个团队相关联。例如：

Randomteam1 = [7, 2, 1, 1, 3], Randomteam2 = [4, 1, 1, 1, 3]

依旧......

现在我希望得到/显示得分最高的前4支球队，以及最低得分的前2支球队。

Answer 1

我可能已经使用过dict但是你可以将列表压缩在一起然后进行排序：

teams = ["Randomteam1","Randomteam2","Randomteam3","Randomteam4","Randomteam5","Randomteam6"]


team_info = [[7, 2, 1, 1, 3], [4, 1, 1, 1, 3],[2, 0, 2, 2, 3], [12, 3, 0, 0, 3], [9, 0, 2, 2, 3], [10, 3, 0, 0, 6]]


data = sorted(zip(teams,team_info),key= lambda x: x[1][0],reverse=True)

[('Randomteam4', [12, 3, 0, 0, 3]), ('Randomteam6', [10, 3, 0, 0, 6]), ('Randomteam5', [9, 0, 2, 2, 3]), ('Randomteam1', [7, 2, 1, 1, 3]), ('Randomteam2', [4, 1, 1, 1, 3]), ('Randomteam3', [2, 0, 2, 2, 3])]

结果是团队按照最高得分的顺序排序，排序键为x[1][0]，这是每个配对中第二个元素的第一个元素，即每个团队的总分数。

前4名将是data[:4]，后两队将是data[-2:]

如果您使用dict，将很容易关联团队并访问任何团队他们的数据，你可以将团队和数据存储为一个字典，并使用排名作为关键：

data = {}
srt = sorted(zip(team_info, teams), reverse=True,1)
for ind, (b,a) in enumerate(srt):
    p, w, l, d, gp = b
    data["rank_{}".format(ind)] = {"team":a,"points": p, "wins": w, "loss": l, "draw": d, "games": gp}



from pprint import pprint as pp

pp(data)

输出：

{'rank_1': {'team': 'Randomteam4',
            'draw': 0,
            'games': 3,
            'loss': 0,
            'points': 12,
            'wins': 3},
 'rank_2': {'team': 'Randomteam6',
            'draw': 0,
            'games': 6,
            'loss': 0,
            'points': 10,
            'wins': 3},
 'rank_3': {'team': 'Randomteam5',
            'draw': 2,
            'games': 3,
            'loss': 2,
            'points': 9,
            'wins': 0},
 'rank_4': {'team': 'Randomteam1',
            'draw': 1,
            'games': 3,
            'loss': 1,
            'points': 7,
            'wins': 2},
 'rank_5': {'team': 'Randomteam2',
            'draw': 1,
            'games': 3,
            'loss': 1,
            'points': 4,
            'wins': 1},
 'rank_6': {'team': 'Randomteam3',
            'draw': 2,
            'games': 3,
            'loss': 2,
            'points': 2,
            'wins': 0}}

Answer 2

您可以对列表进行排序，并使用简单的切片获取元素：

zip

如果您想要团队名称，也可以使用>>> sorted(zip(teams,team_info),key=itemgetter(1,0),reverse=True)[:4] [('Randomteam4', [12, 3, 0, 0, 3]), ('Randomteam6', [10, 3, 0, 0, 6]), ('Randomteam5', [9, 0, 2, 2, 3]), ('Randomteam1', [7, 2, 1, 1, 3])] >>> >>> zip(*sorted(zip(teams,team_info),key=itemgetter(1,0),reverse=True)[:4])[0] ('Randomteam4', 'Randomteam6', 'Randomteam5', 'Randomteam1')：

heapq.nlargest

您还可以使用nsmallest和>>> import heapq >>> heapq.nlargest(4,team_info,key=itemgetter(0)) [[12, 3, 0, 0, 3], [10, 3, 0, 0, 6], [9, 0, 2, 2, 3], [7, 2, 1, 1, 3]] >>> heapq.nsmallest(2,team_info,key=itemgetter(0)) [[2, 0, 2, 2, 3], [4, 1, 1, 1, 3]]来获取N个最大和最小的元素：

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Python：获得2d列表中的前4个最高值

2 个答案: