Question

问题SQL Server: How to Join to first row显示了在SQL中实现的方法。我正在使用光滑的3.0，有三个表：

class ABRelationTable(tag: Tag) extends Table[(Int, Int)](tag, "A_B_RELATION") {
  def aId = column[Int]("A_ID")
  def bId = column[Int]("B_ID")
  def * = (aId, bId)
}

class ACRelationTable(tag: Tag) extends Table[(Int, Int)](tag, "A_C_RELATION") {
  def aId = column[Int]("A_ID")
  def cId = column[Int]("C_ID")
  def * = (aId, cId)
}

class ATable(tag: Tag) extends Table[(Int, String)](tag, "A") {
  def id = column[Int]("ID")
  def data = column[String]("DATA")
  def * = (aId)
}

我想要的是给bId获取对象A和ONE cId。例如：

表A：

ID           DATA
==================
1            101
2            102
3            103

表A_B_RELATION

A_ID         B_ID
=================
1            1
2            1
3            2

表A_C_RELATION

A_ID         C_ID
=================
1            1
2            1
2            2

给定bId = 1，结果可以是：

A_ID     DATA    C_ID
=====================
1        101     1
2        102     1

谢谢！

Answer 1

The following will be your query .

val query = A.join(A_C_RELATION).on(_.ID === _. A_ID) .join(A_B_RELATION).on(_.ID === _. A_ID).filter(_.B_ID ===)

Where A , A_C_RELATION , A_B_RELATION are tablequery of respective tables .

Refer here for more examples.

光滑的3.0＆amp; Postgres 9.4：加入第一行

1 个答案: