Question

实际上我正在为我的业务编写API代码，我的代码有问题，我无法弄清楚问题，这是类：

<?php
class ApiCaller
{
    //some variables for the object
    private $_app_id;
    private $_app_key;
    private $_api_url;

    //construct an ApiCaller object, taking an
    //APP ID, APP KEY and API URL parameter
    public function __construct($app_id, $app_key, $api_url)
    {
        $this->_app_id = $app_id;
        $this->_app_key = $app_key;
        $this->_api_url = $api_url;
    }

    //send the request to the API server
    //also encrypts the request, then checks
    //if the results are valid
    public function sendRequest($request_params)
    {
        //encrypt the request parameters
        $enc_request = base64_encode(mcrypt_encrypt(MCRYPT_RIJNDAEL_256, $this->_app_key, json_encode($request_params), MCRYPT_MODE_ECB));

        //create the params array, which will
        //be the POST parameters
        $params = array();
        $params['enc_request'] = $enc_request;
        $params['app_id'] = $this->_app_id;

        //initialize and setup the curl handler
        $ch = curl_init();
        curl_setopt($ch, CURLOPT_URL, $this->_api_url);
        curl_setopt($ch, CURLOPT_POST, true);
        curl_setopt($ch, CURLOPT_POSTFIELDS, $params);
        curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);

        //execute the request
        $result = curl_exec($ch);

        //json_decode the result
        $result = @json_decode($result);        

        //check if we're able to json_decode the result correctly
        if( $result == false || isset($result->success) == false ) {
            throw new Exception('Request was not correct');         
        }

        //if there was an error in the request, throw an exception
        if( $result->success == false ) {
            throw new Exception($result->errormsg);
        }

        //if everything went great, return the data
        return $result->data;
    }
}

sendRequest函数没有返回数据的问题，只是抛出'请求不正确'异常，我试着测试代码但没有运气。我正在使用xampp-win32-5.6.8-0-VC11，我安装了curl-7.43.0-win64 ,,,

任何帮助将不胜感激，谢谢。

编辑：我使用此代码来测试函数并且它有效：

<?php
$_app_key = '28e336ac6c9423d946ba02d19c6a2632';
$_api_url = 'http://localhost/myAPI/simpletodo_api/';
$_app_id = 'APP001';
$params = array(
    'controller' => 'todo',
    'action' => 'read',
    'username' => 'nikko',
    'userpass' =>'test1234'
);
$enc_request = base64_encode(mcrypt_encrypt(MCRYPT_RIJNDAEL_256, $_app_key, json_encode($params), MCRYPT_MODE_ECB));
$pa = array();
$pa['enc_request'] = $enc_request;
$pa['app_id'] = $_app_id;
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, $_api_url);
curl_setopt($ch, CURLOPT_POST, true);
curl_setopt($ch, CURLOPT_POSTFIELDS, $pa);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
$result = curl_exec($ch);
$errorNo = curl_errno ($ch );
$result = @json_decode($result);
var_dump($result);

结果： “object（stdClass）＃1（2）{[”data“] =＆gt; array（2）{[0] =＆gt; object（stdClass）＃2（5）{[”todo_id“] =＆gt; string（ 10）“1323343689”[“title”] =＆gt; string（10）“test title”[“description”] =＆gt; string（28）“test description weee wasted”[“due_date”] =＆gt; string（10 ）“12/02/2011”[“is_done”] =＆gt; string（4）“true”} [1] =＆gt; object（stdClass）＃3（5）{[“todo_id”] =＆gt; string（ 10）“1323429521”[“title”] =＆gt; string（3）“wee”[“description”] =＆gt; string（11）“adsa wasada”[“due_date”] =＆gt; string（10）“12 / 21/2011“[”is_done“] =＆gt; string（4）”true“}} [”success“] =＆gt; bool（true）}”

那么问题出在哪里呢？

Answer 1

请注意以下几行：

$result = @json_decode($result);

您使用@隐藏了任何错误消息。

我怀疑你没有收到有效的json响应然后$ result会被设置为false，因为json_decode不起作用。

那么如果你没有获得有效的json，会发生什么？您的代码应该处理该错误情况。

为了进行调试，请尝试在var_dump($result);来电后添加curl_exec，这样可以帮助您了解错误。

Answer 2

如评论中所述，您应该检查卷曲错误代码

$errorNo = curl_errno ($ch );

http://php.net/manual/en/function.curl-errno.php

如果是404或其他错误，您无法在代码中知道格式化。

向API服务器发送请求不返回任何内容

2 个答案: