使用多个列

Question

如果我使用多个列来显示子图，如何动态地将新图添加到一组子图中？ This为一列回答了这个问题，但我似乎无法修改那里的答案，使其动态添加到包含x列的子图

我修改了Sadarthrion's answer并尝试了以下内容。在这里，为了举例，我制作了number_of_subplots=11和num_cols = 3。

import matplotlib.pyplot as plt

def plotSubplots(number_of_subplots,num_cols):
    # Start with one
    fig = plt.figure()
    ax = fig.add_subplot(111)
    ax.plot([1,2,3])

    for j in range(number_of_subplots):
        if j > 0: 
            # Now later you get a new subplot; change the geometry of the existing
            n = len(fig.axes)
            for i in range(n):
                fig.axes[i].change_geometry(n+1, num_cols, i+1)

            # Add the new
            ax = fig.add_subplot(n+1, 1, n+1)
            ax.plot([4,5,6])

            plt.show() 

   plotSubplots(11,3) 

正如你所看到的，这并没有给我我想要的东西。第一个图占据了所有列，其他图比它们应该小

修改

('2.7.6 | 64-bit | (default, Sep 15 2014, 17:36:35) [MSC v.1500 64 bit (AMD64)]'

我也有matplotlib版本1.4.3：

import matplotlib as mpl
print mpl.__version__
1.4.3

我在下面尝试了Paul的回答，并收到以下错误消息：

import math

import matplotlib.pyplot as plt
from matplotlib import gridspec

def do_plot(ax):
    ax.plot([1,2,3], [4,5,6], 'k.')


N = 11
cols = 3
rows = math.ceil(N / cols)

gs = gridspec.GridSpec(rows, cols)
fig = plt.figure()
for n in range(N):
    ax = fig.add_subplot(gs[n])
    do_plot(ax)

fig.tight_layout() 
---------------------------------------------------------------------------
TypeError                                 Traceback (most recent call last)
<ipython-input-1-f74203b1c1bf> in <module>()
     15 fig = plt.figure()
     16 for n in range(N):
---> 17     ax = fig.add_subplot(gs[n])
     18     do_plot(ax)
     19 

C:\Users\user\AppData\Local\Enthought\Canopy\User\lib\site-packages\matplotlib\figure.pyc in add_subplot(self, *args, **kwargs)
    962                     self._axstack.remove(ax)
    963 
--> 964             a = subplot_class_factory(projection_class)(self, *args, **kwargs)
    965 
    966         self._axstack.add(key, a)

C:\Users\user\AppData\Local\Enthought\Canopy\User\lib\site-packages\matplotlib\axes\_subplots.pyc in __init__(self, fig, *args, **kwargs)
     73             raise ValueError('Illegal argument(s) to subplot: %s' % (args,))
     74 
---> 75         self.update_params()
     76 
     77         # _axes_class is set in the subplot_class_factory

C:\Users\user\AppData\Local\Enthought\Canopy\User\lib\site-packages\matplotlib\axes\_subplots.pyc in update_params(self)
    113         self.figbox, self.rowNum, self.colNum, self.numRows, self.numCols =     114             self.get_subplotspec().get_position(self.figure,
--> 115                                                 return_all=True)
    116 
    117     def is_first_col(self):

C:\Users\user\AppData\Local\Enthought\Canopy\User\lib\site-packages\matplotlib\gridspec.pyc in get_position(self, fig, return_all)
    423 
    424         figBottoms, figTops, figLefts, figRights = --> 425                     gridspec.get_grid_positions(fig)
    426 
    427 

C:\Users\user\AppData\Local\Enthought\Canopy\User\lib\site-packages\matplotlib\gridspec.pyc in get_grid_positions(self, fig)
    103             cellHeights = [netHeight*r/tr for r in self._row_height_ratios]
    104         else:
--> 105             cellHeights = [cellH] * nrows
    106 
    107         sepHeights = [0] + ([sepH] * (nrows-1))

TypeError: can't multiply sequence by non-int of type 'float' 

Answer 1

假设您的网格至少有一个维度和总图数已知，我会使用gridspec模块和一些数学。

import math

import matplotlib.pyplot as plt
from matplotlib import gridspec

def do_plot(ax):
    ax.plot([1,2,3], [4,5,6], 'k.')


N = 11
cols = 3
rows = int(math.ceil(N / cols))

gs = gridspec.GridSpec(rows, cols)
fig = plt.figure()
for n in range(N):
    ax = fig.add_subplot(gs[n])
    do_plot(ax)

fig.tight_layout()

Answer 2

这是我最终解决的问题。它允许您按名称引用子图，如果尚未使用该名称，则添加新的子图，重新定位过程中的所有先前子图。

用法：

set_named_subplot('plot-a')  # Create a new plot
plt.plot(np.sin(np.linspace(0, 10, 100)))  # Plot a curve

set_named_subplot('plot-b')  # Create a new plot
plt.imshow(np.random.randn(10, 10))   # Draw image

set_named_subplot('plot-a')   # Set the first plot as the current one
plt.plot(np.cos(np.linspace(0, 10, 100)))  # Plot another curve in the first plot

plt.show()  # Will show two plots

代码：

import matplotlib.pyplot as plt
import numpy as np


def add_subplot(fig = None, layout = 'grid'):
    """
    Add a subplot, and adjust the positions of the other subplots appropriately.
    Lifted from this answer: http://stackoverflow.com/a/29962074/851699

    :param fig: The figure, or None to select current figure
    :param layout: 'h' for horizontal layout, 'v' for vertical layout, 'g' for approximately-square grid
    :return: A new axes object
    """
    if fig is None:
        fig = plt.gcf()
    n = len(fig.axes)
    n_rows, n_cols = (1, n+1) if layout in ('h', 'horizontal') else (n+1, 1) if layout in ('v', 'vertical') else \
        vector_length_to_tile_dims(n+1) if layout in ('g', 'grid') else bad_value(layout)
    for i in range(n):
        fig.axes[i].change_geometry(n_rows, n_cols, i+1)
    ax = fig.add_subplot(n_rows, n_cols, n+1)
    return ax


_subplots = {}


def set_named_subplot(name, fig=None, layout='grid'):
    """
    Set the current axes.  If "name" has been defined, just return that axes, otherwise make a new one.

    :param name: The name of the subplot
    :param fig: The figure, or None to select current figure
    :param layout: 'h' for horizontal layout, 'v' for vertical layout, 'g' for approximately-square grid
    :return: An axes object
    """
    if name in _subplots:
        plt.subplot(_subplots[name])
    else:
        _subplots[name] = add_subplot(fig=fig, layout=layout)
    return _subplots[name]


def vector_length_to_tile_dims(vector_length):
    """
    You have vector_length tiles to put in a 2-D grid.  Find the size
    of the grid that best matches the desired aspect ratio.

    TODO: Actually do this with aspect ratio

    :param vector_length:
    :param desired_aspect_ratio:
    :return: n_rows, n_cols
    """
    n_cols = np.ceil(np.sqrt(vector_length))
    n_rows = np.ceil(vector_length/n_cols)
    grid_shape = int(n_rows), int(n_cols)
    return grid_shape


def bad_value(value, explanation = None):
    """
    :param value: Raise ValueError.  Useful when doing conditional assignment.
    e.g.
    dutch_hand = 'links' if eng_hand=='left' else 'rechts' if eng_hand=='right' else bad_value(eng_hand)
    """
    raise ValueError('Bad Value: %s%s' % (value, ': '+explanation if explanation is not None else ''))

Answer 3

from math import ceil
from PyQt5 import QtWidgets, QtCore
from matplotlib.gridspec import GridSpec
from matplotlib.figure import Figure
from matplotlib.backends.backend_qt5agg import FigureCanvasQTAgg as FigureCanvas
from matplotlib.backends.backend_qt5agg import NavigationToolbar2QT as NavigationToolbar


class MplCanvas(FigureCanvas):
    """
    Frontend class. This is the FigureCanvas as well as plotting functionality.
    Plotting use pyqt5.
    """

    def __init__(self, parent=None):
        self.figure = Figure()

        gs = GridSpec(1,1)

        self.figure.add_subplot(gs[0])
        self.axes = self.figure.axes

        super().__init__(self.figure)

        self.canvas = self.figure.canvas
        self.setSizePolicy(QtWidgets.QSizePolicy.Expanding, QtWidgets.QSizePolicy.Expanding)
        self.updateGeometry()
        self.setParent(parent)

    def add(self, cols=2):
        N = len(self.axes) + 1
        rows = int(ceil(N / cols))
        grid = GridSpec(rows, cols)

        for gs, ax in zip(grid, self.axes):
            ax.set_position(gs.get_position(self.figure))

        self.figure.add_subplot(grid[N-1])
        self.axes = self.figure.axes
        self.canvas.draw()

正在做一些PyQt5工作，但add方法显示了如何动态添加新的子图。 Axes的set_position方法用于将旧位置更改为新位置。然后使用新位置添加新的子图。