需要在PHP中打印JSON结果

Question

这里我需要打印来自CURL的json输出。

这是输出

{"call_id":"df0213a216b2af6767955e4052fb084b","to":"XXXXXXXX","status":"0","error_text":"Success"}

类似于call_id值，To值和状态值

这里我的编码和我也试过很少的方法

$phoneno = "Test";

$fields = array('api_key' => 'XXXXX',
            'api_secret' => 'XXXX',
            'to' => 'XXX',
            'from' => 'XXXX',
            'text' => $phoneno);


 $url = 'https://api.nexmo.com/tts/json?' .http_build_query($fields, '', "&");

$ch = curl_init($url);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
$response = curl_exec($ch);
print_r($response);

$json_output = json_decode($response, true);  

echo "Trying to print ### ".$text = $json_output[0]->call_id;     


foreach ($json_output as $trend){         
 echo $trend['call_id']."\n";   
 echo $trend['status']."\n"; 
 echo $trend['error_text']."\n";   
} 

知道怎么做。 ??

Answer 1

这应该有用......

 echo $json_output['call_id']."\n";   
 echo $json_output['status']."\n";
 echo $json_output['error_text']."\n";