我是python的新手,我正在创建一个程序,检查所需的用户是否在数据库中输入了用户名和密码。这是代码:
import mysql.connector
class data:
def __init__(self):
self.usernam = input("Enter user name: ")
self.password= input("Enter Password: ")
a=data()
conn = mysql.connector.connect(host='localhost',user='root',passwd='root',database='user')
loadname= ("select username from user where username='%s'")
mycursor=conn.cursor()
mycursor.execute(a.usernam, loadname)
usercheck=mycursor.fetchone()
loadpass= ("select pass from user where pass ='%s'")
mycursor2=conncursor()
mycursor2.execute(a.password,loadpass)
passcheck=mycursor2.fetchone()
if a.username == usercheck and a.password == passcheck:
print ("pass")
else:
print ("sorry")
conn.commit()
conn.close()
我收到以下错误:
Traceback (most recent call last):
File "C:\Users\HP\Desktop\2nd.py", line 16, in <module>
mycursor.execute(a.usernam, loadname)
File "C:\Python34\lib\site-packages\mysql\connector\cursor.py", line 507, in execute
self._handle_result(self._connection.cmd_query(stmt))
File "C:\Python34\lib\site-packages\mysql\connector\connection.py", line 722, in cmd_query
result = self._handle_result(self._send_cmd(ServerCmd.QUERY, query))
File "C:\Python34\lib\site-packages\mysql\connector\connection.py", line 640, in _handle_result
raise errors.get_exception(packet)
mysql.connector.errors.ProgrammingError: 1064 (42000): You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'asaa' at line 1
答案 0 :(得分:2)
mycursor.execute( loadname,a.username)
首先是查询然后是args ...
我强烈建议您立即切换到像sqlalchemy这样的ORM
答案 1 :(得分:0)
我不知道&#34; mysql.connector&#34;但如果它作为MySQLdb工作,它应该是行的:
mycursor=conn.cursor()
mycursor.execute("select username from user where username=%s", a.username)