Question

我正在尝试创建一个论坛。在这个准备好的声明中，我试图获得forum_topic和forum_posts。此外，在此代码中，我试图查看针对单个主题的帖子，就像您在此处查看我的主题并看到帖子（评论）一样。

我获得了$tid和$cid的正确值。我认为问题必须与我的准备部分有关，但我不太确定。我得到了其他陈述......

echo "<p>This topic does not exist.</p>";

但这是一个实际主题，应该有一个帖子。

有人看到我做错了吗？

我的完整代码：

error_reporting(E_ALL);
ini_set('display_errors', 1);

try {
$con = new mysqli("localhost", "", "", "");
if (mysqli_connect_errno()) {
    throw new Exception("Connect failed: %s\n", mysqli_connect_error());
    exit();
}
$cid = $_GET['cid'];
$tid = $_GET['tid'];
$userid = ( isset( $_SESSION['user'] ) ? $_SESSION['user'] : "" );

//Prepare
if ($stmt = $con->prepare("SELECT * FROM forum_topics WHERE `category_id`=? AND `id`=? LIMIT 1")) {

    $stmt->bind_param("ii", $cid, $tid);
    $stmt->execute();
    $stmt->fetch();


    if (!$stmt) {
        throw new Exception($con->error);
    }
}
$stmt->store_result();
$numrows = $stmt->num_rows;
if($numrows == 1){
    echo "<table width='100%'>";
    if ( $_SESSION['user'] ) { 
        echo "<tr><td colspan='2'><input type='submit' value='Add Reply' onclick=\"window.location = 
    'forum_post_reply.php?cid=".$cid."$tid=".$tid."'\"> <hr />";
    } else {
        echo "<tr><td colspan='2'><p>Please log in to add your reply</p><hr /></td></tr>";
    }

foreach($stmt as $row) {

    //Prepared SELECT stmt to get forum posts
    if($stmt2 = $con->prepare("SELECT * FROM forum_posts WHERE `category_id`=? AND `topic_id`=?")) {
    //var_dump($stmt2);

        $stmt2->bind_param("ii", $cid, $tid);
        $stmt2->execute();
    }   
        while (mysqli_stmt_fetch($stmt)) {
            echo "<tr><td valign='top' style='border: 1px solid #000000;'>
            <div style='min-height: 125px;'>".$row['topic_title']."<br />
            by ".$row2['post_creator']." - " .$row2['post_date']. "<hr />" . $row2['post_content'] ."</div></td>
            <td width='200' valign='top' align='center' style='border: 1px solid #000000;'>User Info Here!</td></tr>
            <tr><td colspan='2'><hr /></td></tr>";
        }
}       
}   else {
    echo "<p>This topic does not exist.</p>";
    }
}
catch (Exception $e)
{
    echo "Error: " . $e->getMessage();
}

我认为显示我想要提取的数据库表可能会有所帮助。

forum_topics
CREATE TABLE `forum_topics` (
 `id` int(11) NOT NULL AUTO_INCREMENT,
 `category_id` int(11) NOT NULL,
 `topic_title` varchar(150) COLLATE utf8_unicode_ci NOT NULL,
 `topic_creator` int(11) NOT NULL,
 `topic_last_user` int(11) DEFAULT NULL,
 `topic_date` datetime NOT NULL,
 `topic_reply_date` datetime NOT NULL,
 `topic_views` varchar(255) COLLATE utf8_unicode_ci NOT NULL DEFAULT '0',
 PRIMARY KEY (`id`)
) ENGINE=MyISAM AUTO_INCREMENT=8 DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_c

forum_posts
CREATE TABLE `forum_posts` (
 `id` int(11) NOT NULL AUTO_INCREMENT,
 `category_id` int(11) NOT NULL,
 `topic_id` int(11) NOT NULL,
 `post_creator` int(11) NOT NULL,
 `post_content` text COLLATE utf8_unicode_ci NOT NULL,
 `post_date` datetime NOT NULL,
 PRIMARY KEY (`id`)
) ENGINE=MyISAM AUTO_INCREMENT=6 DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_c

准备好的声明失败了

0 个答案: