如何使用Spring MVC JSR-303 Validator

时间:2015-07-22 11:12:03

标签: java spring spring-mvc bean-validation hibernate-validator

我在jsp页面内有表格,如下所示:

<springForm:form action="${addAction}" name="frm" method="post" commandName="employee">
    <table>
        <tr>
            <td><label>First Name</label>   </td>
            <td><springForm:input path="firstName" /></td>
            <td><springForm:errors path="firstName" cssClass="error" /></td>
        </tr>
        <tr>
            <td><label>Last Name</label></td>
            <td><springForm:input path="lastName" /></td>
            <td><springForm:errors path="lastName" cssClass="error" /></td>
        </tr>
        <tr>
            <td><label>Email</label>    </td>
            <td><springForm:input path="email" /></td>
            <td><springForm:errors path="email" cssClass="error" /></td>
        </tr>
        <tr>
            <td><label>Street</label>   </td>
            <td><springForm:input path="employeeDetail.street" /></td>
            <td><springForm:errors path="employeeDetail.street" cssClass="error" /></td>
        </tr>
        <tr>
            <td><label>City</label> </td>
            <td><springForm:input path="employeeDetail.city" /></td>
            <td><springForm:errors path="employeeDetail.city" cssClass="error" /></td>
        </tr>
        <tr>
            <td><label>State</label>    </td>
            <td><springForm:input path="employeeDetail.state" /></td>
            <td><springForm:errors path="employeeDetail.state" cssClass="error" /></td>
        </tr>
        <tr>
            <td><label>Country</label>  </td>
            <td><springForm:input path="employeeDetail.country" /></td>
            <td><springForm:errors path="employeeDetail.country" cssClass="error" /></td>
        </tr>
        <tr>
            <td colspan="2" style="text-align: center;">
                <input type="submit" value="Add Info" />
            </td>
        </tr>
    </table>
</springForm:form>

在这个jsp名字中,姓氏和电子邮件属于一个模型类,即Employee。 最后所有属性,如Street,City等属于EmployeeDetails模型类。

public class Employee {

private Long empId;

@Size(min=2, max=30)
private String firstName;

@Size(min=2, max=30)
private String lastName;

@NotEmpty @Email
private String email;

@DateTimeFormat(pattern="MM/dd/yyyy")
@NotNull @Past
private Date doj;

@Phone
private String phone;

private EmployeeDetail employeeDetail;

Getter/Setter
}

EmployeeDetail:

public class EmployeeDetail {

@Size(min=2, max=30)
private String street;

@Size(min=2, max=30)
private String city;

@Size(min=2, max=30)
private String state;

@Size(min=2, max=30)
private String country;
//Getter/Setter
}

我正在单个表单中对两个模型执行验证。我的Cotroller映射是:

@RequestMapping(value = "/saveEmpInfo", method = RequestMethod.POST)
public String saveEmployee(@Valid Employee employee,
        @Valid EmployeeDetail employeeDetail, BindingResult bindingResult) {
    employee.setEmployeeDetail(employeeDetail);
    if (bindingResult.hasErrors()) {
        System.out.println("Returning addInfo.jsp page");
        return "addInfo";
    }
    //future logic
}

但它无法获得错误请求。enter image description here

2 个答案:

答案 0 :(得分:4)

要完成这项工作,您应该在Employee.class中使用@Valid注释employeeDetails,如下所示:

@Valid
private EmployeeDetail employeeDetail;

现在在控制器中你应该只使用这样的Employee对象:

public String saveEmployee(@Valid Employee employee, BindingResult bindingResult) {

答案 1 :(得分:1)

您应该更改属于EmployeeDetail的属性的名称,例如name="street"name="employeeDetail.street"

此外,您还应在BindingResult参数后面添加一个Employee对象,以便框架可以存储与Employee相关的绑定错误,当前BindingResult将仅应用于{{1实例,所以

EmployeeDetail

没有它你得到一个错误的请求,用它,请求实际上会到达方法,如果设置为调试级别,日志将显示确切的绑定错误

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