Question

我们在mysql 5.6中使用这个common_schema库来从json数组中提取值。格式如下。但它返回NULL值。那么，请你帮我们解决如何使用common_schema解析json数组。

select common_schema.extract_json_value('"batter":
[
     { "id": "1001", "type": "Regular" },
     { "id": "1002", "type": "Chocolate" },
     { "id": "1003", "type": "Blueberry" },
     { "id": "1004", "type": "Devils Food" }
]','/id');

预期输出应保存在表格中

   id    type
  1001  Regular
  1002  Chocolate
  1003  Blueberry
  1004  Devils Food

请告诉我们如何实现此解析。

由于格利扬

Answer 1

直接看起来并不容易得到你需要的东西。

获取单个值的选项是：

SET @`json` := '
{
    "batter":
        [
            { "id": "1001", "type": "Regular" },
            { "id": "1002", "type": "Chocolate" },
            { "id": "1003", "type": "Blueberry" },
            { "id": "1004", "type": "Devils Food" }
        ]
}
';

SELECT
    `common_schema`.`extract_json_value`(@`json`,'descendant-or-self::id[1]') `id`,
    `common_schema`.`extract_json_value`(@`json`,'descendant-or-self::type[1]') `type`;

+------+---------+
| id   | type    |
+------+---------+
| 1001 | Regular |
+------+---------+
1 row in set (0,04 sec)

使用common_schema库无法解析json数组值

1 个答案: