Question

我想做的是：

if (article.find("(")) and not (article.find(")")):

然而，它似乎不起作用。任何帮助表示赞赏。谢谢！

Answer 1

NSString *Str_embbed_video = [NSString stringWithFormat:@"\
                              <html><head>\
                              <style type=\"text/css\">\
                              body {\
                              background-color: black;\
                              color: transparent;\
                              }\
                              </style>\
                              </head><body style=\"margin:0\">\
                              <video width=\"%0.0f\" height=\"%0.0f\" controls autoplay=\"true\" poster=\"%@\" webkit-playsinline\> <source src=\"%@\" type=\"video/mp4\" ></video>\
                              </body></html>",webviewFrame.size.width,webviewFrame.size.height,imageurlString,videoUrlString];


[webView loadHTMLString:Str_embbed_video baseURL:[[NSBundle mainBundle] resourceURL]];

你想要失败时返回0的东西。 Help on built-in function find: find(...) S.find(sub [,start [,end]]) -> int Return the lowest index in S where substring sub is found, such that sub is contained within S[start:end]. Optional arguments start and end are interpreted as in slice notation. Return -1 on failure.运算符执行此操作。

Answer 2

使用in，and not in。

if '(' in article and not ')' in article:

示例：

>>> a = '(sdk' >>> if '(' in a and not ')' in a: print('yah') yah >>> a = '(sdk)' >>> if '(' in a and not ')' in a: print('yah') >>> a = 'sdk' >>> if '(' in a and not ')' in a: print('yah') >>>

Answer 3

$('table').on('click', 'td:nth-child(3)', function () {

  $(this).next().toggle();
  // |     |
  // |     ^-- this selects the next sibling
  // |
  // ^-- `this` is a reference to the clicked td
});

检查字符串是否包含字符，并且不包含其他字符

3 个答案: