while($record = mysql_fetch_array($myData)){
if(($record['Opponent'] == "") && ($record['better_name'] != $_SESSION['user_name'])){
$acceptID = "accept" . $record['bet_ID'];
echo "<form action=index.php method=post>";
echo "<input type=submit name=" . $acceptID . " value="ACCEPT">";
echo "<input type=hidden id=" . $record['bet_ID'] . ">";
echo "</form>";
} elseif (($record['Opponent'] == "") && ($record['better_name'] == $_SESSION['user_name'])){
echo "<form action=index.php method=post>";
echo "<input type=submit name=delete value=DELETE>";
echo "<input type=hidden id=" . $record['bet_ID'] . ">";
echo "</form>";
} else {
echo "Game Locked.";
答案 0 :(得分:0)
我试图通过$_POST['ACCEPT']
和$_POST['DELETE']
命令传递bet_ID&#39; s。事实证明,我并不需要每个输入/按钮的表格。这对我有用:
## $record['bet_ID'] was pulled from an SQL database table.
echo "<input type=hidden name=accept value='$record[bet_ID]'>";
echo "<input type=submit value=Accept>";
$date = $_POST['accept'];
echo $date;