Question

我想知道是否有办法让python 2.7按照字母顺序按类中的字符串对类进行排序。

class person: #set up for patient
def __init__(self, FName, LName):
    self.FName = FName  # the first name of patient
    self.LName = LName  # last name of patient

patients=person(raw_input('first name'),raw_input('second name'))
i=1
all=[patients]
orderAlphabet=[patients]
orderInjury=[patients]
print a[0]
while i<3:
   patients=person(raw_input('first name'),raw_input('second name'))
   a.append(patients)
   i = i+1

我试图在这个例子中按姓氏排序。

Answer 1

我们假设您想按姓氏对患者进行分类。

班级代码是：

class person: #set up for patient
def __init__(self, FName, LName):
    self.FName = FName  # the first name of patient
    self.LName = LName  # last name of patient

您可以使用以下方式接收用户的输入：

i = 1
patients=person(raw_input('first name'),raw_input('second name'))
a=[patients] #You have used 'all'
while(i < 3):
    patients=person(raw_input('first name'),raw_input('second name'))
    a.append(patients) #And you have used 'a' here.
    i = i + 1

要按照姓氏对患者进行排序，您可以使用：

orderAlphabet=[a[i].LName for i in range(0,3)]
orderAlphabet = orderAlphabet.sort()

Answer 2

operator.attrgetter对此非常有用。

Route::group(['middleware' => ['auth','auth_admin']], function () {
    // Admin routes here
});

from operator import attrgetter a.sort(key=attrgetter('LName')) #sorts in-place print(a) #list should be sorted here.也可以使用多个参数。因此，如果您想按姓氏排序，然后按名字排序，请执行attrgetter

Answer 3

class person: #set up for patient
    def __init__(self, FName, LName):
        self.FName = FName  # the first name of patient
        self.LName = LName  # last name of patient
    def __str__(self,):
        return 'FName:'+ self.FName + ', LName:' + self.LName

persons = [person('1', 'd'), person('3', 'c'), person('2', 'b')]

persons2 = sorted(persons, key=lambda p: p.FName)  # sort by FName
persons3 = sorted(persons, key=lambda p: p.LName)  # sort by LName
persons4 = sorted(persons, key=lambda p: p.LName, reverse=True) # sort by LName with reverse order

for p in persons2:
    print p

print 

for p in persons3:
    print p

print 

for p in persons4:
    print p

输出：

FName:1, LName:d
FName:2, LName:b
FName:3, LName:c

FName:2, LName:b
FName:3, LName:c
FName:1, LName:d

FName:1, LName:d
FName:3, LName:c
FName:2, LName:b

基于类python 2.7中的变量按字母顺序对类列表进行排序

3 个答案: