以下是目前使用的代码。
public String getStringFromDoc(org.w3c.dom.Document doc) {
try
{
DOMSource domSource = new DOMSource(doc);
StringWriter writer = new StringWriter();
StreamResult result = new StreamResult(writer);
TransformerFactory tf = TransformerFactory.newInstance();
Transformer transformer = tf.newTransformer();
transformer.transform(domSource, result);
writer.flush();
return writer.toString();
}
catch(TransformerException ex)
{
ex.printStackTrace();
return null;
}
}
答案 0 :(得分:80)
public String getStringFromDoc(org.w3c.dom.Document doc) {
DOMImplementationLS domImplementation = (DOMImplementationLS) doc.getImplementation();
LSSerializer lsSerializer = domImplementation.createLSSerializer();
return lsSerializer.writeToString(doc);
}
答案 1 :(得分:13)
这更简洁:
try {
Transformer transformer = TransformerFactory.newInstance().newTransformer();
StreamResult result = new StreamResult(new StringWriter());
DOMSource source = new DOMSource(doc);
transformer.transform(source, result);
return result.getWriter().toString();
} catch(TransformerException ex) {
ex.printStackTrace();
return null;
}
否则你可以使用像Apache的XMLSerializer这样的库:
//Serialize DOM
OutputFormat format = new OutputFormat (doc);
// as a String
StringWriter stringOut = new StringWriter ();
XMLSerializer serial = new XMLSerializer (stringOut,format);
serial.serialize(doc);
// Display the XML
System.out.println(stringOut.toString());
答案 2 :(得分:12)
变换器API是从DOM对象转换为序列化形式(在本例中为String)的唯一XML标准方法。作为标准,我的意思是SUN Java XML API for XML Processing。
其他替代方法(如Xerces XMLSerializer或JDOM XMLOutputter)是更直接的方法(代码更少),但它们是特定于框架的。
在我看来,你使用的方式是最优雅,最便携的。通过使用标准XML Java API,您可以在不更改代码的情况下插入您选择的XML-Parser或XML-Transformer(与JDBC驱动程序相同)。还有比这更优雅的东西吗?
答案 3 :(得分:8)
您可以使用XOM来执行此操作:
org.w3c.dom.Document domDocument = ...;
nu.xom.Document xomDocument =
nu.xom.converters.DOMConverter.convert(domDocument);
String xml = xomDocument.toXML();