Question

我想添加一个搜索框，使用%like%搜索内容。

我已经尝试了太多，但得到的错误数量。

我已经应用了这样的查询：

<?php
    //including the database connection file
    include_once("config.php");

    //fetching data in descending order (lastest entry first)
    $result = mysql_query("SELECT * FROM users ORDER BY id DESC");
    ?>



      <html>
        <head>  
            <title>Homepage</title>
        </head>

        <body>
        <a href="add.html">Add New Data</a><br/><br/>

            <table width='80%' border=0>

            <tr bgcolor='#CCCCCC'>
                <td>Name</td>
                <td>Age</td>
                <td>Email</td>
                <td>Update</td>
            </tr>
            <?php 
            while($res = mysql_fetch_array($result)) {      
                echo "<tr>";
                echo "<td>".$res['name']."</td>";
                echo "<td>".$res['age']."</td>";
                echo "<td>".$res['email']."</td>";  
                echo "<td><a href=\"edit.php?id=$res[id]\">Edit</a> | <a href=\"delete.php?id=$res[id]\" onClick=\"return confirm('Are you sure you want to delete?')\">Delete</a></td>";       
            }
            ?>
            </table>
        </body>
        </html>

Answer 1

<form method="POST">
<input name="search" type="text">
<button type="submit">Search</button>
</form>
<?php
if($_POST){
    $data = $_POST['search'];
    $q = mysql_query("SELECT * FROM `users` LIKE '%$data%' ORDER BY id DESC");
while($res = mysql_fetch_array($q)) {      
        echo "<tr>";
        echo "<td>".$res['name']."</td>";
        echo "<td>".$res['age']."</td>";
        echo "<td>".$res['email']."</td>";  
        echo "<td><a href=\"edit.php?id=$res[id]\">Edit</a> | <a href=\"delete.php?id=$res[id]\" onClick=\"return confirm('Are you sure you want to delete?')\">Delete</a></td>";
        echo "</tr>";       
    }
}
?>

P.S。不推荐使用mysql，使用mysqli和良好的转义或mysqli预处理语句或PDO

添加搜索框以使用％like％搜索内容

1 个答案: