好的,如果我使用代码:
$phrase = "You should eat fruits, vegetables, and fiber every day.";
$healthy = array("fruits", "vegetables", "fiber");
$yummy = array("pizza", "beer", "ice cream");
$newphrase = str_replace($healthy, $yummy, $phrase);
// Provides: You should eat pizza, beer, and ice cream every day
但是如果我要替换的单词列表是变量怎么办。
$sample1 = "fruits, vegetables, fiber";
$sample2 = "pizza, beer, ice cream";
$phrase = "You should eat fruits, vegetables, and fiber every day.";
$healthy = array($sample1);
$yummy = array($sample2);
$newphrase = str_replace($healthy, $yummy, $phrase);
// Provides: You should eat fruits, vegetables, and fiber every day.
如果我使用相同:
$sample1 = '"fruits", "vegetables", "fiber"';
$sample1 = '"pizza", "beer", "ice cream"';
$phrase = "You should eat fruits, vegetables, and fiber every day.";
$healthy = array($sample1);
$yummy = array($sample2);
$newphrase = str_replace($healthy, $yummy, $phrase);
我错过了什么吗?
有没有办法轻松做到这一点?
答案 0 :(得分:0)
你需要将字符串转换为数组,在这种情况下使用explode:
$sample1 = "fruits, vegetables, fiber";
$sample2 = "pizza, beer, ice cream";
$phrase = "You should eat fruits, vegetables, and fiber every day.";
$healthy = explode(',',$sample1);
$yummy = explode(',',$sample2);
$newphrase = str_replace($healthy, $yummy, $phrase);
答案 1 :(得分:0)
您可以使用分隔符将string
array
分解为$sample1 = "fruits, vegetables, fiber";
$sample2 = "pizza, beer, ice cream";
$phrase = "You should eat fruits, vegetables, and fiber every day.";
$healthy = explode(",", $sample1);
$yummy = explode(",", $sample2);
$newphrase = str_replace($healthy, $yummy, $phrase);
:
trim()
我建议您在每个字符串之间没有空格。如果您要这样做,那么您可能希望array_map()
每个值。 $healthy = array_map('trim', explode(",", $sample1));
在这里很有用,因为您可以将函数映射到每个值,如下所示:
$sample1 = "fruits , vegetables,fiber";
$sample2 = "pizza, beer,ice cream";
$phrase = "You should eat fruits, vegetables, and fiber every day.";
$healthy = array_map('trim', explode(",", $sample1));
$yummy = array_map('trim', explode(",", $sample2));
$newphrase = str_replace($healthy, $yummy, $phrase);
所以整件事情更像是:
np.atleast_2d