对于方法

Question

我正在尝试编写一个code，根据随机机会将值更改为-1或+1。它基本上是一个穿过街区的人。他从6开始，如果他在1结束他赢了，但如果他在11结束他输了。最终输出看起来像这样：

   Here we go again... time for a walk!
   Walked 37 blocks, and
   Landed at Home

   Here we go again... time for a walk!
   Walked 19 blocks, and
   Landed in JAIL

   Here we go again... time for a walk!
   Walked 13 blocks, and
   Landed in JAIL

   Here we go again... time for a walk!
   Walked 25 blocks, and
   Landed in JAIL

我写了以下代码：

public class Drunk {
    public int street;
    public double move;
    public int i;
    public boolean jail;

   public static void drunkWalk() {
       do {
           street = 6;
           move = Math.random();
           i++;
           if (move > 0.5) {
               street++;
           } else {
               street--;
           }
       } while (street != 1 && street != 11);
       if ( street == 1) {
           jail = false;
       } else {
           jail = true;
       }
    for (; ; ) { --- } //This is the problem. It treats it as a method. 
                     //How can I fix this?
    }
}

Answer 1

有些想法如下：

public static void main(String args[])
{
    Drunk drunk = new Drunk();
    while (true) 
     { 
         DrunkResult result = drunk.drunkWalkToJail();
         System.out.println("Walked " + result.getSteps() + " blocks, and Landed at " + (result.isInJail() ? "Jail":"Home"));
     } 
}
public DrunkResult drunkWalkToJail()
{
    int street;
    int stepCount = 0;

    do
    {
        street = 6;
        double move = Math.random();
        stepCount++;
        if (move > 0.5)
        {
            street++;
        }
        else
        {
            street--;
        }
    }
    while (street != 1 && street != 11);

    return new DrunkResult(street == 11, stepCount);
}

和

public class DrunkResult
{
    boolean jail = false;

    int stepCount = 0;

    public DrunkResult(boolean jail, int stepCount)
    {
        this.jail = jail;
        this.stepCount = stepCount;
    }

    public boolean isInJail()
    {
        return jail;
    }

    public int getSteps()
    {
        return stepCount;

    }

}

你可以并行行走（一群醉酒的人）并独立处理结果。