我是Scala的新手,我写了一段代码,将员工档案(empId,姓名,年龄,薪水,部门)作为输入,打印出部门和部门的总薪水。
这是一个新手代码。如何缩短代码?请帮忙
代码:
object UsingCollectionMaps {
def main(a: Array[String]) {
val filename = "Employee.txt"
var map = collection.mutable.Map[String,Long]()
var sal: Long = 0
for (line <- Source.fromFile(filename).getLines()) {
val fields = line.split(",")
if (map.contains(fields(4))) {
map.put(fields(4), (map(fields(4)) + fields(3).toLong))
} else {
map.put(fields(4), fields(3).toLong)
}
}
println(map)
}
}
答案 0 :(得分:8)
我会尽量避免这些可变结构,并且也要理解这个文件,将它正确地分配给一个case类。 之后,使用groupBy和sum。
import scala.io.Source
case class Employee(empId: String, name: String, age: Int,
salary: Long, department: Int)
Source.fromFile("someFile.txt")
.getLines()
.map( _.split(",") )
.map( l => Employee(l(0), l(1), l(2).toInt,
l(3).toLong, l(4).toInt) )
.toSeq
.groupBy( _.department )
.mapValues( _.map( _.salary ).sum )
答案 1 :(得分:4)
您可以使用.groupBy
方法创建一个Map
的部门&#39; - &GT; &#39;雇员&#39;然后总结他们的工资:
object UsingCollectionMaps {
def main(a:Array[String]){
val filename = "Employee.txt"
val lines = io.Source.fromFile(filename).getLines().toList
val map = employees.map(_.split(","))
.groupBy(_(4)) // Group by the fourth element of the arrays
.mapValues(_.map(_(3).toLong).sum) // Map an employeeList to their salaries and sum them
println(map)
}
}
答案 2 :(得分:3)
这不会短得多,但确实需要采用更实用的方法:
import collection.immutable.Map
import io.Source
object UsingCollectionMaps {
def main(args: Array[String]) {
println(
Source.fromFile("Employee.txt").getLines()
.foldLeft(Map.empty[String, Long])({
case (totals, line) =>
val fields = line.split(",")
val department = fields(4)
val salary = fields(3).toLong
totals.updated(department,
totals.getOrElse(department, 0L) + salary)
})
)
}
}