如何索引aws快照输出?

时间:2015-07-21 18:56:04

标签: amazon-web-services go

这里我正在打印我的快照。我在下面发布了我希望快照打印出来的样子,并且还希望能够打印单个快照。我不知道如何做到这一点任何帮助都会很棒。

svc := ec2.New(&aws.Config{Region: "us-east-1"})
params := &ec2.DescribeSnapshotsInput{
    OwnerIDs: []*string{
        aws.String("130300684064"),
    },
}

b, err2 := svc.DescribeSnapshots(params)
if err2 != nil {
    panic(err2)
}
fmt.Printf(awsutil.StringValue(b))

以下是输出内容:http://imgur.com/3MnBNXI 这就是我想要输出的内容:

{

Snapshots:

----0

  Description: "Snapshot from MULTI",

  Encrypted: false,

  OwnerID: "130300684064",

  Progress: "100%!"(MISSING),

  SnapshotID: "snap-81b1dff6",

  StartTime: 2015-07-21 18:41:54 +0000 UTC,

  State: "completed",

  VolumeID: "vol-5121ebaa",

  VolumeSize: 1

},{

----1

  Description: "Snapshot from MULTI",

  Encrypted: false,

  OwnerID: "130300684064",

  Progress: "100%!"(MISSING),

  SnapshotID: "snap-08352a7f",

  StartTime: 2015-07-21 18:41:54 +0000 UTC,

  State: "completed",

  VolumeID: "vol-9b21eb60",

  VolumeSize: 1

},{

----2

  Description: "Snapshot from MULTI",

  Encrypted: false,

  OwnerID: "130300684064",

  Progress: "100%!"(MISSING),

  SnapshotID: "snap-768ffb00",

  StartTime: 2015-07-21 18:41:54 +0000 UTC,

  State: "completed",

  VolumeID: "vol-5620eaad",

  VolumeSize: 1

}]

此处的完整代码:http://pastebin.com/QgmV6kRj

1 个答案:

答案 0 :(得分:0)

如果要打印各个快照的详细信息,可以迭代响应:

resp, err := svc.DescribeSnapshots(params)
if err != nil {
    log.Fatal(err)
}
for i, s := range resp.Snapshots {
    fmt.Printf("Snapshot: %d\n", i)
    fmt.Println(s)
}