Question

我正在尝试发送一个简单的电子邮件表单，一切正常，但我仍然在正文消息的末尾收到收件人的电子邮件。我检查了PHP代码，但我找不到为什么再次显示该电子邮件，这里是PHP代码：

$name = $_POST['name']; 
$company = $_POST['company'];
$website = $_POST['website'];
$visitor_email = $_POST['email']; 
$message = $_POST['message'];

$email_from = 'juano.diy@gmail.com';//<== update the email address
$email_subject = "New Form submission";
$email_body = "You have received a new message from the user $name.\n".
"Company: $company.\n".
"Website: $website.\n".
"Contact Email: $visitor_email.\n".
"Here is the message:\n$message.\n".
"\n".                                                                                                                                                           

$to = "juano.diy@gmail.com";//<== update the email address
$headers = "From: $email_from \r\n";
$headers .= "Reply-To: $visitor_email \r\n";
//Send the email!
mail($to,$email_subject,$email_body,$headers);

我将以下列形式介绍这些细节：

Name: xxx
Company: xxx
website: www.xxx.com
email: xxx@live.com
message: Hi testing email

这就是我收到的内容：

You have received a new message from the user Juan Camilo. 
Company: Blitzar.
Website: www.stiktag.com.
Contact Email: juano.diy@live.com.
Here is the message:
Hi, testing website.

juano.diy@gmail.com

问题是最后一行（juano.diy@gmail.com），当我已经将它添加到标题中时，为什么我会收到该地址，我不想在那里看到它，有什么想法？

Answer 1

float A=24000000; float B= A + 1; //~1 error here的最后一行正在连接。

$email_body

将最后一行替换为$email_body = "You have received a new message from the user $name.\n". "Company: $company.\n". "Website: $website.\n". "Contact Email: $visitor_email.\n". "Here is the message:\n$message.\n". "\n". "\n". - 注意分号。这将终止分配。

PHP表单添加食谱电子邮件

1 个答案: