Question

我有一个字符串，想要在一些字符之后将其拆分......

示例代码：

    //This is what I have:
    String text = "12345678";
    List<String> tmpListFirst = new LinkedList<>();
    List<String> tmpListSecond = new LinkedList<>();
    int splitAfter = 3; //split after the second character (this value is variable)

    //The result should look like this:
    tmpListFirst.get(0) //== 678
    tmpListFirst.get(0) //== 12345

Answer 1

String text = "12345678";
int splitAfter = 3;
List<String> tmpListFirst = new LinkedList<>();
List<String> tmpListSecond = new LinkedList<>();
tmpListFirst.add(text.substring(0, splitAfter));
tmpListSecond.add(text.substring(splitAfter));

如果您想要存储在列表中的值，那就是

。否则它们只能通过执行String s1 = text.substring(0, splitAfter);和/而存储在字符串中 String s2 = text.substring(splitAfter);

Answer 2

String text = "12345678";
text = text.substring(0, 1) //will print 1
text = text.substring(3, text.length()) //will print 45678
text = text.substring(3) //will also print 45678

应该是您正在寻找的。比在n个字符

之后使用String.split（）方法容易得多

Answer 3

试试这段代码。这将为您提供完全理想的结果：

String text = "12345678";
List<String> tmpListFirst = new LinkedList<>();
List<String> tmpListSecond = new LinkedList<>();
int splitAfter = 5; //split after the second character (this value is variable)

//The result should look like this:
tmpListFirst.add(text.substring(splitAfter));//678
tmpListSecond.add(text.substring(0, splitAfter)); //== 12345

System.out.println(tmpListFirst.get(0));
System.out.println(tmpListSecond.get(0));

如果您不需要使用List或LinkedList，那么程序将非常简单，如： -

String text = "12345678";
int splitAfter = 5; //split after the second character (this value is variable)

System.out.println(text.substring(splitAfter)); //678
System.out.println(text.substring(0, splitAfter)); //12345

Answer 4

如果我理解正确，你想要像

那样做

String text = "12345678";
System.out.println(text.substring(0, 5));
System.out.println(text.substring(5));

//-----------output-------------
12345
678

Java - 在字符数后分割？

4 个答案: