Question

我试图提示用户确认他们想在退出前关闭程序。如果任务仍在执行，我想确认仍然希望退出或让他们有机会在退出之前完成任务。我使用了setOnCloseRequest，但它没有用。我使用了event.consume，似乎只是禁用了[x]按钮。任何建议表示赞赏。我发现这里有一个类似的问题对我不起作用 - ＆gt; JavaFX stage.setOnCloseRequest without function?

Public class Sample extends Application {
      @Override
    public void start(Stage stage) throws Exception {

    stage.setOnCloseRequest(event -> {
        NewScanView checkScan = new NewScanView();
        boolean isScanning = checkScan.isScanning();

            Alert alert = new Alert(AlertType.CONFIRMATION);
            alert.setTitle("Close Confirmation");
            alert.setHeaderText("Cancel Creation");
            alert.setContentText("Are you sure you want to cancel creation?");
        if (isWorking == true){

            Optional<ButtonType> result = alert.showAndWait();
            if (result.get() == ButtonType.OK){
                stage.close();
            }

            if(result.get()==ButtonType.CANCEL){
                alert.close();
            }

        }


    });
    stage.setHeight(600);
    stage.setWidth(800);
    stage.setTitle("Title");
    stage.show();

}

public static void main(String[] args) {
    launch(args);
}

}

Answer 1

此答案基于Javafx internal close request的答案。这个问题与这个问题不同，但答案非常相似。

import javafx.application.Application;
import javafx.event.EventHandler;
import javafx.geometry.Insets;
import javafx.scene.Scene;
import javafx.scene.control.*;
import javafx.scene.layout.StackPane;
import javafx.stage.*;
import javafx.stage.WindowEvent;

import java.util.Optional;

public class CloseConfirm extends Application {

    private Stage mainStage;

    @Override
    public void start(Stage stage) throws Exception {
        this.mainStage = stage;
        stage.setOnCloseRequest(confirmCloseEventHandler);

        Button closeButton = new Button("Close Application");
        closeButton.setOnAction(event ->
                stage.fireEvent(
                        new WindowEvent(
                                stage,
                                WindowEvent.WINDOW_CLOSE_REQUEST
                        )
                )
        );

        StackPane layout = new StackPane(closeButton);
        layout.setPadding(new Insets(10));

        stage.setScene(new Scene(layout));
        stage.show();
    }

    private EventHandler<WindowEvent> confirmCloseEventHandler = event -> {
        Alert closeConfirmation = new Alert(
                Alert.AlertType.CONFIRMATION,
                "Are you sure you want to exit?"
        );
        Button exitButton = (Button) closeConfirmation.getDialogPane().lookupButton(
                ButtonType.OK
        );
        exitButton.setText("Exit");
        closeConfirmation.setHeaderText("Confirm Exit");
        closeConfirmation.initModality(Modality.APPLICATION_MODAL);
        closeConfirmation.initOwner(mainStage);

        // normally, you would just use the default alert positioning,
        // but for this simple sample the main stage is small,
        // so explicitly position the alert so that the main window can still be seen.
        closeConfirmation.setX(mainStage.getX());
        closeConfirmation.setY(mainStage.getY() + mainStage.getHeight());

        Optional<ButtonType> closeResponse = closeConfirmation.showAndWait();
        if (!ButtonType.OK.equals(closeResponse.get())) {
            event.consume();
        }
    };

    public static void main(String[] args) {
        launch(args);
    }

}

答案确实使用event.consume()，你说你尝试过并且不适合你（虽然我不知道为什么不能，因为这对我来说这个示例代码很合适）。

Answer 2

尝试创建一个弹出框（如果你还没有），点击退出后会提示用户。如果他们选择＆＃34; Ok＆＃34;然后调用exit方法，否则返回到你正在做的任何事情。

这是一个网页，其中包含如何编写弹出窗口的示例，因为文档完全是垃圾。 https://gist.github.com/jewelsea/1926196

用户尝试在JavaFx中使用setOnCloseRequest关闭应用程序时的警报框

2 个答案: