Question

这有点具体，所以请耐心等待......

我希望我的where语句能够提供符合以下条件的所有结果：

WHERE
TestCode = A1 
AND
TestResult > 50
AND
TestCode = A2
AND
TestResult > 200

实际上，我想要一份既有A1>50又有A2 > 200

的患者的清单

我可以看到这不会起作用＆＃34;按照＆＃34;因为我给了这两个更大的子句，但是我添加括号来表示我想要的东西，它不会返回任何数据。

原始（不工作）查询

      AND 
(SQLUser.EP_VisitTestSetData.VISTD_TestCode_DR  =  'A0165'  AND  SQLUser.EP_VisitTestSetData.VISTD_TestData  >  '35')
  AND  
(SQLUser.EP_VisitTestSetData.VISTD_TestCode_DR  =  'A0155'  AND  SQLUser.EP_VisitTestSetData.VISTD_TestData  >  '25')
)

工作代码

      AND 
((SQLUser.EP_VisitTestSetData.VISTD_TestCode_DR  =  'A0165'  AND  SQLUser.EP_VisitTestSetData.VISTD_TestData  >  '35') OR (SQLUser.EP_VisitTestSetData.VISTD_TestCode_DR  =  'A0155'  AND  SQLUser.EP_VisitTestSetData.VISTD_TestData  >  '25'))
  AND  
((SQLUser.EP_VisitTestSetData.VISTD_TestCode_DR  =  'A0155'  AND  SQLUser.EP_VisitTestSetData.VISTD_TestData  >  '25') OR (SQLUser.EP_VisitTestSetData.VISTD_TestCode_DR  =  'A0165'  AND  SQLUser.EP_VisitTestSetData.VISTD_TestData  >  '35'))

抱歉格式化...

Answer 1

我认为您之后的语法是：

SELECT * 
FROM    your_table AS A
WHERE   EXISTS (
            SELECT TOP 1 1 
            FROM    your_table AS A1_50
            WHERE   A1_50.ID = A.ID
                AND A1_50.TestCode = 'A1'
                AND A1_50.TestResult > 50)
    AND EXISTS (
            SELECT TOP 1 1 
            FROM    your_table AS A2_200
            WHERE   A2_200.ID = A.ID
                AND A2_200.TestCode = 'A2'
                AND A2_200.TestResult > 200)

只需将your_table替换为您要查询的表格，并使用您要检查以获得分数＆gt;的patient_id列。 50/200

编辑：您也可以使用INTERSECT：

SELECT  PatientID 
FROM    your_table 
WHERE   TestCode = 'A1'
    AND TestResult > 50
INTERSECT 
SELECT  PatientID 
FROM    your_table 
WHERE   TestCode = 'A2'
    AND TestResult > 200

Answer 2

我认为你想要这样的东西（猜测表和字段名称）：

SELECT * from Patients p1
WHERE EXISTS (SELECT NULL FROM Patients p2 
              WHERE p1.ID = p2.ID
                 AND p2.TestCode = A1 AND p2.TestResult > 50)  
  AND EXISTS (SELECT NULL FROM Patients p2 
              WHERE p1.ID = p2.ID
              AND p2.TestCode = A2 AND p2.TestResult > 200)

Answer 3

这样的东西应该适用于几乎每个rdbms：

SELECT *
FROM YourTable t1
WHERE TestCode = 'A1' AND TestResult > 50
AND EXISTS(
   SELECT 1
   FROM YourTable t2 
   WHERE t2.patientId = t1.PatientId
   AND TestCode = 'A2' AND TestResult > 200
)

Answer 4

问题是没有行都有TestCode = A1和TestCode = A2。您可以将条件更改为

WHERE (TestCode = A1 AND TestResult > 50) OR (TestCode = A2 AND TestResult > 200)

或像这样使用UNION：

SELECT * FROM foo WHERE TestCode = 'A1' AND TestResult > 50 UNION SELECT * FROM foo WHERE TestCode = 'A2' AND TestResult > 50

Answer 5

我想你的表看起来像这样：

TestCode    TestResult   PersonId
A1           30           1
A1           60           2
A1           90           3
A2           60           3
A2           90           1
A2          120           2

然后你可以这样做：

SELECT t1.PersonId 
FROM TestData t1
INNER JOIN TestData t2 on t1.PersonId = t2.PersonId
WHERE t1.TestCode = 'A1' AND t2.TestCode = 'A2'
AND t1.TestResult > 50
AND t2.TestResult > 100;

Answer 6

您需要join到TestCode两次的表格，一次用于A1测试，一次用于A2测试。然后你的where条款可以是：

WHERE a1.TestResult > 50 AND a2.TestResult > 200

Answer 7

如果您希望患者通过两个测试，那么我建议group by使用having条款：

select PatientId
from . ..
group by PatientId
having sum(case when SQLUser.EP_VisitTestSetData.VISTD_TestCode_DR = 'A0165'  AND  
                     SQLUser.EP_VisitTestSetData.VISTD_TestData  >  '35'
                then 1 else 0 end) > 0 and
       sum(case when SQLUser.EP_VisitTestSetData.VISTD_TestCode_DR = 'A0155'  AND
                      SQLUser.EP_VisitTestSetData.VISTD_TestData  >  '25'
                then 1 else 0 end) > 0;

sum()子句中的每个having计算条件为真的记录数。 > 0确保至少有一条此类记录。

我喜欢这种方法，因为它很灵活 - 你可以轻松地添加另一个测试，或测试三个测试中的两个。

Answer 8

你想做这样的事吗？

 WHERE ((TestCode = A1) AND (TestResult > 50)) OR ((TestCode = A2) AND (TestResult > 200))

看起来您正在测试WHEN TestCode = 'A1' AND WHEN TestCode = 'A2'这对他们来说是不可能同时等于两者，返回为空。

SQL满足条件a且满足条件b无结果

8 个答案: