Question

我已成功将Google+整合到我的iOS应用中。但随着最新的Apple商店更新，该应用程序不允许打开浏览器使用safari启动Google身份验证，所以我尝试使用uiwebview进行googleplus身份验证，我获取访问令牌，但我无法获取用户名和电子邮件地址登录的人。我添加了我的来源，

NSString *client_id = @"***************************";;
NSString *secret = @"*******************************";
NSString *callbakc =  @"https://www.example.com/oauth2callback";;
NSString *scope = @"https://www.googleapis.com/auth/userinfo.email+https://www.googleapis.com/auth/userinfo.profile+https://www.google.com/reader/api/0/subscription";
NSString *visibleactions = @"http://schemas.google.com/AddActivity";

@interface MainViewController ()

@end

@implementation MainViewController
@synthesize webview,isLogin,isReader;

- (void)viewDidLoad
{
      [super viewDidLoad];


NSString *url = [NSString stringWithFormat:@"https://accounts.google.com/o/oauth2/auth?response_type=code&client_id=%@&redirect_uri=%@&scope=%@&data-requestvisibleactions=%@",client_id,callbakc,scope,visibleactions];

[webview loadRequest:[NSURLRequest requestWithURL:[NSURL URLWithString:url]]];
}
- (BOOL)webView:(UIWebView*)webView shouldStartLoadWithRequest:(NSURLRequest*)request navigationType:(UIWebViewNavigationType)navigationType {
//    [indicator startAnimating];


NSLog(@"dgfduiussdiff %@ ",[[request URL] host]);

if ([[[request URL] host] isEqualToString:@"www.example.com"]) {

    // Extract oauth_verifier from URL query
    NSString* verifier = nil;
    NSArray* urlParams = [[[request URL] query] componentsSeparatedByString:@"&"];
    for (NSString* param in urlParams) {
        NSArray* keyValue = [param componentsSeparatedByString:@"="];
        NSString* key = [keyValue objectAtIndex:0];
        if ([key isEqualToString:@"code"]) {
            verifier = [keyValue objectAtIndex:1];
            NSLog(@"verifier %@",verifier);
            break;
        }
    }

    if (verifier) {
        NSString *data = [NSString stringWithFormat:@"code=%@&client_id=%@&client_secret=%@&redirect_uri=%@&grant_type=authorization_code", verifier,client_id,secret,callbakc];
        NSString *url = [NSString stringWithFormat:@"https://accounts.google.com/o/oauth2/token"];
        NSMutableURLRequest *request = [[NSMutableURLRequest alloc] initWithURL:[NSURL URLWithString:url]];
        [request setHTTPMethod:@"POST"];
        [request setHTTPBody:[data dataUsingEncoding:NSUTF8StringEncoding]];
        NSURLConnection *theConnection=[[NSURLConnection alloc] initWithRequest:request delegate:self];
        receivedData = [[NSMutableData alloc] init];

    } else {
        // ERROR!
    }

    [webView removeFromSuperview];

    return NO;
}
return YES;
}

- (void)connection:(NSURLConnection *)connection didReceiveData:(NSData *)data

    {
     NSError* error;

[receivedData appendData:data];


NSDictionary* json = [NSJSONSerialization
                      JSONObjectWithData:receivedData
                      options:kNilOptions
                      error:&error];

NSLog(@"verifier %@",json);



 }
           - (void)connection:(NSURLConnection *)connection didFailWithError:     (NSError *)error{
UIAlertView *alert = [[UIAlertView alloc] initWithTitle:@"Error"
                                                message:[NSString stringWithFormat:@"%@", error]
                                               delegate:nil
                                      cancelButtonTitle:@"OK"
                                      otherButtonTitles:nil];
  [alert show];
}  

- (void)connectionDidFinishLoading:(NSURLConnection *)connection
{
NSString *response = [[NSString alloc] initWithData:receivedData encoding:NSUTF8StringEncoding];
SBJsonParser *jResponse = [[SBJsonParser alloc]init];
NSDictionary *tokenData = [jResponse objectWithString:response];
//  WebServiceSocket *dconnection = [[WebServiceSocket alloc] init];
//   dconnection.delegate = self;

NSString *pdata = [NSString stringWithFormat:@"type=3&token=%@&secret=123&login=%@", [tokenData objectForKey:@"refresh_token"], self.isLogin];
//  NSString *pdata = [NSString stringWithFormat:@"type=3&token=%@&secret=123&login=%@",[tokenData accessToken.secret,self.isLogin];
//  [dconnection fetch:1 withPostdata:pdata withGetData:@"" isSilent:NO];


UIAlertView *alertView = [[UIAlertView alloc]
                          initWithTitle:@"Google Access TOken"
                          message:pdata
                          delegate:nil
                          cancelButtonTitle:@"OK"
                          otherButtonTitles:nil];
[alertView show];
 }

执行上述源后，我在nslog中打印出以下响应，

       verifier 4/kMcSZ2l-d_XXPo24NSdsMnugoP_MGDGPP4D5C1LRTfY
      2015-07-21 18:04:16.103 TechnoGerms.com[8981:189233] verifier {
     "access_token" =        "ya29.twG9kyMElyC8BgAxujF98WKN0BQ246Ey6zsKQEgSpKsNEb5JOS3QRl12La6XBy1geZnL";
"expires_in" = 3600;
      "id_token" = "eyJhbGciOiJSUzI1NiIsImtpZCI6ImRhNjYyNWIzNmJjMDlkMzAwMzUzYjI4YTc0MWNlMTc1MjVhNGMzM2IifQ.eyJpc3MiOiJhY2NvdW50cy5nb29nbGUuY29tIiwic3ViIjoiMTE0MjE4NDEwODI0NzM1ODkyMDg0IiwiYXpwIjoiMTY5NzY2MjI4OTY4LWtoNzI1dTFpZWdzNHN1bnFhOThhcHUxMHU4djhhcmFmLmFwcHMuZ29vZ2xldXNlcmNvbnRlbnQuY29tIiwiZW1haWwiOiJhcmp1bkBsaW5rd2FyZS5pbiIsImF0X2hhc2giOiJQVnJxTURpNDViZnVGTm9kTmlsSFlRIiwiZW1haWxfdmVyaWZpZWQiOnRydWUsImF1ZCI6IjE2OTc2NjIyODk2OC1raDcyNXUxaWVnczRzdW5xYTk4YXB1MTB1OHY4YXJhZi5hcHBzLmdvb2dsZXVzZXJjb250ZW50LmNvbSIsImhkIjoibGlua3dhcmUuaW4iLCJpYXQiOjE0Mzc0ODIwNTUsImV4cCI6MTQzNzQ4NTY1NX0.uSMrV8rOz4T4i5MhiCeQueNVGLv4NBLP-gtOcyow8t4BY9qvUO78sG4y0jPhbclPdX1kUZjzMVTeah2nU9fTYyl50dlj5FzWNy7LyM-a1GC2jEwkgWMgHdRPh6l7dqMrjQ9sU1rF-ZaiWfG7C9VJTJ76uEWRiSKKA9EFQtBil3xBtmDH07UMRxkbri2jBwaCPAWgjU8-dTarrxNESrwrO_nptaRzfGeaTyQBIYCAk6_9deXmblPgteER1OHoa65xb1OVK3ZPeZ3_dj9gjlXSyGp2ho5WIFGf2xRvW4XoROpUYqhLvrS3s-YrrZ8J5X5-3mafrs1qDjJYJogctbW7dg";
     "token_type" = Bearer;
   }

如何使用我上面获得的访问令牌获取登录用户的用户名和电子邮件？请提供任何建议，因为我在谷歌上没有得到任何解决方案。

感谢您的支持

Answer 1

如果您想要获取Google +用户的整个个人资料，可以使用以下网址

https://www.googleapis.com/plus/v1/people/me/?access_token={YOUR_ACCESS_TOKEN}

然后调用 GET 方法。您将通过包含授权配置文件详细信息的数组给出。

另一种方法是，如果您要存储授权用户的电子邮件，则其已在字段中显示为 id_token 。它是带有一些字段的base64_encoded数据。如果您解码id，则会获得有关用户的一些信息。例如，在您的结果中，您发现id_token为

eyJhbGciOiJSUzI1NiIsImtpZCI6ImRhNjYyNWIzNmJjMDlkMzAwMzUzYjI4YTc0MWNlMTc1MjVhNGMzM2IifQ.eyJpc3MiOiJhY2NvdW50cy5nb29nbGUuY29tIiwic3ViIjoiMTE0MjE4NDEwODI0NzM1ODkyMDg0IiwiYXpwIjoiMTY5NzY2MjI4OTY4LWtoNzI1dTFpZWdzNHN1bnFhOThhcHUxMHU4djhhcmFmLmFwcHMuZ29vZ2xldXNlcmNvbnRlbnQuY29tIiwiZW1haWwiOiJhcmp1bkBsaW5rd2FyZS5pbiIsImF0X2hhc2giOiJQVnJxTURpNDViZnVGTm9kTmlsSFlRIiwiZW1haWxfdmVyaWZpZWQiOnRydWUsImF1ZCI6IjE2OTc2NjIyODk2OC1raDcyNXUxaWVnczRzdW5xYTk4YXB1MTB1OHY4YXJhZi5hcHBzLmdvb2dsZXVzZXJjb250ZW50LmNvbSIsImhkIjoibGlua3dhcmUuaW4iLCJpYXQiOjE0Mzc0ODIwNTUsImV4cCI6MTQzNzQ4NTY1NX0.uSMrV8rOz4T4i5MhiCeQueNVGLv4NBLP-gtOcyow8t4BY9qvUO78sG4y0jPhbclPdX1kUZjzMVTeah2nU9fTYyl50dlj5FzWNy7LyM-a1GC2jEwkgWMgHdRPh6l7dqMrjQ9sU1rF-ZaiWfG7C9VJTJ76uEWRiSKKA9EFQtBil3xBtmDH07UMRxkbri2jBwaCPAWgjU8-dTarrxNESrwrO_nptaRzfGeaTyQBIYCAk6_9deXmblPgteER1OHoa65xb1OVK3ZPeZ3_dj9gjlXSyGp2ho5WIFGf2xRvW4XoROpUYqhLvrS3s-YrrZ8J5X5-3mafrs1qDjJYJogctbW7dg

上面的id_token包含由'。'分隔的2个部分。第一部分是base64_encoded密钥，第二部分是元数据。

您可以将数据解码为

$key=base64_decode(eyJhbGciOiJSUzI1NiIsImtpZCI6ImRhNjYyNWIzNmJjMDlkMzAwMzUzYjI4YTc0MWNlMTc1MjVhNGMzM2IifQ)

会给你钥匙

$data=base64_decode(eyJpc3MiOiJhY2NvdW50cy5nb29nbGUuY29tIiwic3ViIjoiMTE0MjE4NDEwODI0NzM1ODkyMDg0IiwiYXpwIjoiMTY5NzY2MjI4OTY4LWtoNzI1dTFpZWdzNHN1bnFhOThhcHUxMHU4djhhcmFmLmFwcHMuZ29vZ2xldXNlcmNvbnRlbnQuY29tIiwiZW1haWwiOiJhcmp1bkBsaW5rd2FyZS5pbiIsImF0X2hhc2giOiJQVnJxTURpNDViZnVGTm9kTmlsSFlRIiwiZW1haWxfdmVyaWZpZWQiOnRydWUsImF1ZCI6IjE2OTc2NjIyODk2OC1raDcyNXUxaWVnczRzdW5xYTk4YXB1MTB1OHY4YXJhZi5hcHBzLmdvb2dsZXVzZXJjb250ZW50LmNvbSIsImhkIjoibGlua3dhcmUuaW4iLCJpYXQiOjE0Mzc0ODIwNTUsImV4cCI6MTQzNzQ4NTY1NX0.uSMrV8rOz4T4i5MhiCeQueNVGLv4NBLP-gtOcyow8t4BY9qvUO78sG4y0jPhbclPdX1kUZjzMVTeah2nU9fTYyl50dlj5FzWNy7LyM-a1GC2jEwkgWMgHdRPh6l7dqMrjQ9sU1rF-ZaiWfG7C9VJTJ76uEWRiSKKA9EFQtBil3xBtmDH07UMRxkbri2jBwaCPAWgjU8-dTarrxNESrwrO_nptaRzfGeaTyQBIYCAk6_9deXmblPgteER1OHoa65xb1OVK3ZPeZ3_dj9gjlXSyGp2ho5WIFGf2xRvW4XoROpUYqhLvrS3s-YrrZ8J5X5-3mafrs1qDjJYJogctbW7dg)

会为您提供元数据。

在解码数据时，它会将结果显示为

{"iss":"accounts.google.com","sub":"114218410824735892084","azp":"169766228968-kh725u1iegs4sunqa98apu10u8v8araf.apps.googleusercontent.com","email":"arjun@linkware.in","at_hash":"PVrqMDi45bfuFNodNilHYQ","email_verified":true,"aud":"169766228968-kh725u1iegs4sunqa98apu10u8v8araf.apps.googleusercontent.com","hd":"linkware.in","iat":1437482055,"exp":1437485655}

以上结果您可以找到电子邮件字段。我希望这会对你有所帮助。

ios中的GooglePlus集成

1 个答案: