Question

我正在使用 SQL-Server 2008 。我需要将行与相同的Name组合在一起，并在以下情况下增加计数器：

同一Id's的{{1}} Name为blank
如果Id为NULL，则不合并行
如果具有相同的Name但不同的Ids

现在输出：

Name    Id   Cnt
John    1     1
Peter   2     2 -- This Peter with the same Id have 2 entries so Cnt = 2
Peter   3     1 -- This is other Peter with 1 entry so Cnt = 1
Lisa    4     1
Lisa   NULL   1
David   5     1
David         1 -- here Id is blank ''
Ralph         2 -- Ralph have both rows with blank Id so Cnt = 2

期望的输出：

Name    Id   Cnt
John    1     1
Peter   2     2
Peter   3     1
Lisa    4     1
Lisa   NULL   1 -- null still here
David   5     2 -- merged with blank '' so Cnt = 2
Ralph         2 -- merged both blanks '' so Cnt = 2

SQL-Query：

这是我现在正在使用的示例查询：

SELECT Name, 
       Id, 
       COUNT(Id) AS Cnt
FROM Employees                       
WHERE Condition = 1                 
GROUP BY Name, Id

我尝试了什么：

在MAX子句中向Id添加了汇总SELECT，仅按Name分组，但在这种情况下，合并的行具有NULL值并且具有相同的值不同Id's的名字对我来说有什么不对。

SELECT Name, 
       MAX(Id), -- added aggregate
       COUNT(Id) AS Cnt
FROM Employees                       
WHERE Condition = 1                 
GROUP BY Name -- grouped by Name only

你有什么想法吗？如果对问题一无所知 - 请问我，我会提供更多细节。

更新

DDL

CREATE TABLE Employees
(
  Name NVARCHAR(40),
  Id NVARCHAR(40)
);

DML

INSERT INTO Employees VALUES
 ('John' ,   '1')
,('Peter',   '2')
,('Peter',   '2')
,('Peter',   '3')
,('Lisa' ,   '4')
,('Lisa' ,  NULL)
,('David',   '5')
,('David',   '')
,('Ralph',   '')
,('Ralph',   '')

DEMO： this link

Answer 1

您可以在$(document).on('mouseup', '.m1', function(){ alert('div mouseup '); }); $(document).on('click', 'ul li', function(){ alert("ul li- clicked"); });内使用CASE声明。它允许您为员工空白时设置Id = [some value]。查询可以是这样的：

SELECT

Answer 2

修改

DECLARE @Data table (Name varchar(10), Id varchar(10)) -- Id must be varchar for blank value INSERT @Data VALUES ('John', '1'), ('Peter', '2'),('Peter', '2'), ('Peter', '3'),--('Peter', ''), --For test ('Lisa', '4'), ('Lisa', NULL), ('David', '5'), ('David', ''), ('Ralph', ''), ('Ralph', '')

SELECT Name, Id, COUNT(*) + ISNULL( (SELECT COUNT(*) FROM @data WHERE Name = d.Name AND Id = '' AND d.Id <> '') , 0) AS Cnt FROM @data d WHERE Id IS NULL OR Id <> '' OR NOT EXISTS(SELECT * FROM @data WHERE Name = d.Name AND Id <> '') GROUP BY Name, Id

Answer 3

具有窗口功能的版本：

SELECT Name,ID, Cnt from
( select *, sum(1-AmtBlank) over (partition by Name, ID) + sum(case id when 0 then 1 else 0 end) over (partition by Name) Cnt,
       rank()  over (partition by Name order by AmtBlank  ) rnk,
       row_number() over (partition by Name, ID order by AmtBlank) rnr
    FROM (select * , case id when '' then 1 else 0 end AmtBlank from Employees /*WHERE Condition = 1*/ ) e
) c where  rnr=1 and rnk = 1

这使用case id when '' then 1 else 0 end AmtBlank来保留每行空白金额（使非空白1-AmtBlank的金额）和2个窗口函数的金额，一个id为每个名称和id的计数（{{1 }和）名称部分中所有空格的计数（sum(1-AmtBlank) over (partition by Name, ID)） sum(case id when 0 then 1 else 0 end) over (partition by Name)用于随后仅获取组的第一行，而row_number仅用于在没有id的记录时包含空白记录。

Answer 4

试试这个。使用cte和join

;with cte as (
SELECT Name, 
       Id, 
       COUNT(*) AS Cnt
FROM Employees                       
WHERE isnull(Id,1)<>''               
GROUP BY Name, Id
),

cte2 as (SELECT Name,id, COUNT(*) AS Cnt    FROM Employees WHERE Id='' GROUP BY Name,id)

select cte.Name,cte.Id,(cte.cnt + ISNULL(cte2.Cnt,0)) as cnt
from cte 
left JOIN  cte2
on cte.Name = cte2.Name 
union all 
select cte2.Name,cte2.Id,cte2.cnt
from cte2 
left JOIN  cte
on cte.Name = cte2.Name 
where cte.Name is null

Answer 5

这个简单的语法与旧版本或其他RDBMS兼容 - 自我解释评论
的编辑：

select name, id, count(*) from ( -- adds "normal" records select name, id from Employees where id is null or id <> '' -- adds one record to each name-notBlankId for each blank id (David, Peter if you add 'Peter','') -- uncomment /*or id is null*/ if you want even null ids to recieve merged blanks union all select e1.name, e1.id from (select distinct name, id from Employees where id <> '' /*or id is null*/ ) as e1 inner join (select name, id from Employees where id = '') as e2 on e1.name = e2.name -- adds records that can't be merged (Ralph) union all select name, id from Employees e1 where e1.id = '' and not exists(select * from Employees e2 where e1.name = e2.name and e2.id <> '') ) as fullrecords group by name, id

Answer 6

你可以尝试这样的事情。

;WITH NonBlanks AS
(
  SELECT Name, 
         Id, 
         COUNT(ISNULL(Id, 1)) AS Cnt
  FROM Employees
  WHERE ISNULL(Id,0) <> ''
  GROUP BY Name, Id
 )
,Blanks AS
(
  SELECT Name, 
         Id, 
         COUNT(ISNULL(Id, 1)) AS Cnt
  FROM Employees
  WHERE ID = ''
  GROUP BY Name, Id
)
SELECT CASE WHEN nb.NAME IS NULL THEN b.NAME ELSE nb.NAME END NAME,
       CASE WHEN nb.NAME IS NULL THEN b.Id ELSE nb.Id END Id,
       (ISNULL(nb.Cnt,0) + ISNULL(b.Cnt,0)) Cnt
FROM NonBlanks nb FULL JOIN  Blanks b 
     ON nb.Name = b.Name

如果值为空，则合并行

6 个答案: