我有一个appium测试程序,在google nexus 5上完全正常,但在三星Galaxy Tab 4和android 5.0.2中没有

时间:2015-07-21 07:35:26

标签: android selenium appium

我有一个appium测试程序,在google nexus 5和android 5.1.1上工作得很好但是当我用android 5.0.2为三星Galaxy Tab 4配置测试时程序开始运行,应用程序安装并打开很好但是一旦第一页出现,就没有任何事情发生了。

遵循所需的功能和第一次测试

@Test
public void test0() throws MalformedURLException, InterruptedException {

File app = new File("C:\\Users\\Samila\\Documents\\Mobile_Research\\Apk\\android-debug.apk");


        DesiredCapabilities caps = DesiredCapabilities.android();
        caps.setCapability(CapabilityType.BROWSER_NAME, "");
        caps.setCapability("deviceName","samsung-sm_t530nu");
        caps.setCapability("platformVersion", "5.0.2");
        caps.setCapability("deviceOrientation", "landscape");
        caps.setCapability("platformName", "Android");
        caps.setCapability("app", app.getAbsolutePath());


        aadr = new AndroidDriver<>(new URL("http://127.0.0.1:4723/wd/hub"), caps);      


    }





    @Test
    public void test1() throws Exception {

        //Wait until application open correctly
        WebDriverWait wait = new WebDriverWait(aadr, 40);




        //Locate URL , User Name and Password
        wait.until(ExpectedConditions.presenceOfElementLocated(By.className("android.widget.EditText")));
        wait.until(ExpectedConditions.presenceOfElementLocated(By.name("test.orangehrm.com")));
        MobileElement url = (MobileElement) aadr.findElements(By.className("android.widget.EditText")).get(0);
        MobileElement userName = (MobileElement) aadr.findElements(By.className("android.widget.EditText")).get(1);
        MobileElement password = (MobileElement) aadr.findElements(By.className("android.widget.EditText")).get(2);
        System.out.println(url);System.out.println(userName);System.out.println(password);System.out.println(" ");

        for(int i=0;i<3;i++){
            MobileElement test = (MobileElement) aadr.findElements(By.className("android.widget.EditText")).get(i);
            System.out.println(i+" "+ test.getId());
        }

        System.out.println(" ");
        Thread.sleep(30000);
        //Test 1- Press Login button with the Empty URL, User Name & Password
        url.click();
        Thread.sleep(30000);
        for(int i=0;i<20;i++){aadr.sendKeyEvent(67);}
        aadr.hideKeyboard();

        //Wait till button is available on the screen
        wait.until(ExpectedConditions.presenceOfElementLocated(By.className("android.widget.Button")));
        MobileElement loginBtn = (MobileElement)aadr.findElements(By.className("android.widget.Button")).get(1);

        //Tap the Login button
        TouchAction btn = new TouchAction(aadr);
        btn.tap(loginBtn).perform();

        wait.until(ExpectedConditions.presenceOfElementLocated(By.className("android.view.View")));

        Thread.sleep(1000);
        MobileElement warninigMsg = (MobileElement) aadr.findElements(By.className("android.view.View")).get(9);

        //Assert whether Username empty warning message is coming or not
        assertEquals("Username is Empty",warninigMsg.getAttribute("name"));

0 个答案:

没有答案