Question

我希望比较数据库中的用户名和密码（如果存在），如果不是成功，如果不是抛出错误我使用 SQLiteOpenHelper 来完成任务我现在可以从数据库中获取一个字段如何检索多个字段

 public UserInfo get_user_by_id(String id) {
        SQLiteDatabase db = this.getReadableDatabase();
        UserInfo userInfo = null;

        Cursor cursor = db.query(TABLE_NAME, new String[]{COLUMN_APP_ID}, COLUMN_APP_ID + "=?", new String[]{id + ""}, null, null, null);

           while (cursor.moveToNext()) {
               //userInfo.setAppId(cursor.getString(cursor.getColumnIndex(COLUMN_APP_ID)));
               userInfo = new UserInfo(cursor.getString(cursor.getColumnIndex(COLUMN_APP_ID)));
           }

请提前帮助我

Answer 1

从方法get_user_by_id（）返回UserInfo列表。

public ArrayList<UserInfo> get_user_by_id(String id) {
    ArrayList<UserInfo> listUserInfo = new ArrayList<UserInfo>();
    SQLiteDatabase db = this.getReadableDatabase();
    Cursor cursor = db.query(TABLE_NAME, new String[]{COLUMN_APP_ID}, COLUMN_APP_ID + "=?", new String[]{id + ""}, null, null, null);

    if (cursor != null) {

        while (cursor.moveToNext()) {
          UserInfo userInfo = new UserInfo();
          userInfo.setAppId(cursor.getString(cursor.getColumnIndex(COLUMN_APP_ID)));
          // HERE YOU CAN MULTIPLE RECORD AND ADD TO LIST 
          listUserInfo.add(userInfo);
        }
    }
 return listUserInfo;
}

Answer 2

像这样使用SQLite Query ....

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从SQLite数据库中检索多个字段并与这些字段进行比较

2 个答案: