Question

我正在尝试编写一个程序，可以将13张扑克牌从ace换成王牌。交出2张牌并加上分配给每张牌的价值。 ace = 11，king = 10，jack = 10，queen = 10，ten = 10,9 = 9,8 = 8等等......有点像二十一点。

到目前为止，我只能随机播放这些卡并随机打印出两张卡，但我不知道如何为每张卡分配一个值，将它们加起来并打印出来。例如，如果我的两张随机卡是King和Eight，那么我希望程序打印出来..

景

八

18

这就是我得到的......

        static void Main(string[] args)
    {
        string[] Cards = new string[] {"Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine", "Ten", "jack", "Queen", "King", "Ace"};

        for (int x = 0; x < 100; x++) // looping the shuffle 100 times to maximize the randomness
        {
            for (int i = Cards.Length; i > 0; i--) //shuffle
            {
                string temp;
                Random random = new Random();
                int r = random.Next(i);
                temp = Cards[r];
                Cards[r] = Cards[i-1];
                Cards[i-1] = temp;
            }  
        }
        Console.WriteLine(Cards[0]); //first random card
        Console.WriteLine(Cards[1]); //second random card
        Console.ReadKey();
    }

Answer 1

有关卡片游戏编程的一个很好的例子，请从书籍Beginning Visual C＃2012中搜索KarliCards（您可以轻松找到完整的PDF，但我不会发布链接，因为我＆＃39;我不确定它是否合法）。它有很多东西，比如如何在类或结构等事物上使用常规运算符（+）。

无论如何，你要找的是一个枚举。它与Rob建议的字典（字符串）（int）非常相似（我不确定如何编写三角括号）。以下是其工作原理的示例：

    enum CardValue
    {
        One = 1,
        Two = 2,
        Three = 3,
        Four = 4
    }

    static void Main(string[] args)
    {
        int myInt = (int)CardValue.One;
        Console.WriteLine("output should be 1: " + myInt);

        int mySum = (int)CardValue.One + (int)CardValue.Three;
        Console.WriteLine("output should be 4: " + mySum);
        Console.ReadKey();
    }

我的第一语言是Perl，因此我倾向于将所有内容都视为结构而不是类。总有不止一种方法可以做到....

    public enum CardSuits
    {
        Clubs,
        Spades,
        Hearts,
        Diamonds
    }

    public enum CardValues
    {
        Ace = 1,
        Two = 2,
        Three = 3,
        Four = 4
    }

    public struct Card
    {
        public CardValues Value; // Card.Value = CardValues.Ace
        public CardSuits Suit; // Card.Suit = CardSuits.Spades

        public override string ToString()
        {
            // Card.ToString() == "Ace of Spades"
            return String.Format(Value + " of " + Suit); 
        }

        public string ToStringAsInteger()
        {
            // Card.ToStringAsInteger() == "1 of Spades"
            return String.Format((int)Value + " of " + Suit); 
        }
    }

    static void Main(string[] args)
    {
        Card AceOfSpades = new Card();
        AceOfSpades.Value = CardValues.Ace;
        AceOfSpades.Suit = CardSuits.Spades;

        Card TwoOfClubs = new Card();
        TwoOfClubs.Value = CardValues.Two;
        TwoOfClubs.Suit = CardSuits.Clubs;

        int mySum = (int)AceOfSpades.Value + (int)TwoOfClubs.Value;
        Console.WriteLine("Sum of Ace (1) and Two (2) is: " + mySum); // should be 3
        Console.WriteLine("output of AceOfSpades.ToString() is: " + AceOfSpades.ToString());
        Console.WriteLine("output of AceOfSpades.ToStringAsInteger is: " + AceOfSpades.ToStringAsInteger());

        Console.ReadKey();
    }

Answer 2

我将如何做到这一点：

var cards = new Dictionary<string, int>()
{
    { "Two", 2 }, { "Three", 3 }, { "Four", 4 }, { "Five", 5 }, { "Six", 6 },
    { "Seven", 7 }, { "Eight", 8 }, { "Nine", 9 }, { "Ten", 10 }, { "Jack", 10 },
    { "Queen", 10 }, { "King", 10 }, { "Ace", 11 },
};

var random = new Random();

var selected = cards.OrderBy(c => random.Next()).Take(2).ToArray();

foreach (var card in selected)
{
    Console.WriteLine(card.Key);
}

Console.WriteLine(selected.Sum(c => c.Value));

运行这个，我得到（例如）：

Two
Ten
12

现在，只是了解有关现有代码的更多信息。

在循环内调用Random random = new Random();将导致许多（如果不是全部）随机数相同。您应该只使用Random的单个实例。

不需要for (int x = 0; x < 100; x++)循环，因为for (int i = Cards.Length; i > 0; i--)循环的单次传递足以随机化卡片。

C＃为数组赋值

2 个答案: