问题:我怎样才能让它成为一个无限循环,其中"查看更多"然后按钮会在步骤3之后重新出现,从而允许重复?
这里是jQuery:
$(document).ready(function() {
//Hides the new row to prepare for click event
$('.images-section').children('.new-row').hide();
//Creating variables for see more/less buttons
var more = $('.images-button-more');
var less = $('.images-button-less');
less.hide();
//Add new row on click of see more button
more.on('click', function() {
$('.images-section').children('.new-row').show(function() {
$(this).insertAfter('.old-row').slideDown('1000');
more.fadeOut('slow', function() {
less.insertAfter(more).fadeIn('slow');
});
});
});
//Remove new row on click of see less button
less.on('click', function() {
$('.new-row').slideUp('1000', function() {
less.fadeOut('slow');
});
});
});
这是HTML:
<section class="no-padding remove-tablet">
<div class="container-fluid images-section">
<div class="row no-gutter old-row">
<div class="col-lg-2 col-sm-6">
<img src="img/ant-johns.jpg" class="img-responsive" alt="Ant Johns" width="317px" height="322px">
</div>
<div class="col-lg-2 col-sm-6">
<img src="img/white-guy.jpg" class="img-responsive" alt="Arnold Jr" width="317px" height="322px">
</div>
<div class="col-lg-2 col-sm-6">
<img src="img/enrique-double-bi.jpg" class="img-responsive" alt="Enrique Double Bi" width="317px" height="322px">
</div>
<div class="col-lg-2 col-sm-6">
<img src="img/anthony-b.jpg" class="img-responsive" alt="Anthony B" width="317px" height="322px">
</div>
<div class="col-lg-2 col-sm-6">
<img src="img/manny-most-muscular.jpg" class="img-responsive" alt="Manny Most Muscular" width="317px" height="322px">
</div>
<div class="col-lg-2 col-sm-6">
<img src="img/remi-model-tats.jpg" class="img-responsive" alt="Remi Model Tats" width="317px" height="322px">
</div>
</div>
<div class="row no-gutter new-row">
<div class="col-lg-2 col-sm-6">
<img src="img/ant-johns.jpg" class="img-responsive" alt="Ant Johns" width="317px" height="322px">
</div>
<div class="col-lg-2 col-sm-6">
<img src="img/white-guy.jpg" class="img-responsive" alt="Arnold Jr" width="317px" height="322px">
</div>
<div class="col-lg-2 col-sm-6">
<img src="img/enrique-double-bi.jpg" class="img-responsive" alt="Enrique Double Bi" width="317px" height="322px">
</div>
<div class="col-lg-2 col-sm-6">
<img src="img/anthony-b.jpg" class="img-responsive" alt="Anthony B" width="317px" height="322px">
</div>
<div class="col-lg-2 col-sm-6">
<img src="img/manny-most-muscular.jpg" class="img-responsive" alt="Manny Most Muscular" width="317px" height="322px">
</div>
<div class="col-lg-2 col-sm-6">
<img src="img/remi-model-tats.jpg" class="img-responsive" alt="Remi Model Tats" width="317px" height="322px">
</div>
</div>
<div class="row">
<div class="col-sm-12 text-center">
<a class="images-button-more" style="padding-bottom: 3px; border-bottom: 1px dotted rgb(130,181,65); position: relative; top: 5px; cursor: pointer; text-decoration: none; border-radius: 50%">See more</a>
</div>
<div class="col-sm-12 text-center">
<a class="images-button-less" style="padding-bottom: 3px; border-bottom: 1px dotted rgb(130,181,65); position: relative; top: 5px; cursor: pointer; text-decoration: none; border-radius: 50%">See less</a>
</div>
</div>
</div>
</section>
我尝试将jQuery放在if语句周围,然后输入新变量,如&#34; isClosed,isNotClosed&#34;,然后根据某些事件将其值从0更改为1,如果isClosed为true则循环,但是这对我没有任何正义。
答案 0 :(得分:2)
一个选项是在页面加载时加载第二行图像,但使用display: none
隐藏它并为其指定id='second-row'
然后在您的点击事件中,您可以执行以下操作:
$('#buttonId').on('click', function() {
$('#second-row').slideToggle();
});
答案 1 :(得分:1)
您只是在jquery中错过了一行:
less.on('click', function() {
$('.new-row').slideUp('1000', function() {
less.fadeOut('slow');
more.insertAfter(less).fadeIn('slow');//this line
});
});