Question

我无法将视图链接到我正在构建的电子商务模板中的基本HttpResponse。

我得到的错误是404，但经过这里查看以及文档说我对我错过的内容感到有些困惑，

模型

   from django.db import models

class Category(models.Model):
    parent = models.ForeignKey('self', null=True, blank=True)
    name = models.CharField(max_length=255)
    slug = models.SlugField(max_length=150)
    description = models.TextField()
    pub_date = models.DateTimeField(auto_now_add=True)
    mod_date = models.DateTimeField(auto_now=True)

class Manufacturer(models.Model):
    name = models.CharField(max_length=150)
    slug = models.SlugField(max_length=150)


class Product(models.Model):
    category = models.ForeignKey(Category)
    manufacturer = models.ForeignKey(Manufacturer)
    name = models.CharField(max_length=300)
    slug = models.SlugField(max_length=150)
    description = models.TextField()
    photo = models.ImageField(upload_to='itemphotos')
    price_in_sterling = models.DecimalField(max_digits =6, decimal_places=2)
    available = models.BooleanField()
    instock = models.IntegerField()
    pub_date = models.DateTimeField(auto_now_add=True)
    mod_date = models.DateTimeField(auto_now=True)

我的views.py

    from django.shortcuts import render
    from django.http import HttpResponse

    def index(request):
        return HttpResponse("Hi, your view worked")

    def catagory(request):
        return HttpResponse("Hi, you are looking at the catagory landing page")

    def manufacturer(request):
        return HttpResponse("Hi, here you can shop by brand")

    def product(request):
        return HttpResponse("Hi, here you can search by product")

我的urls.py

from django.conf.urls import include, url
from django.contrib import admin


urlpatterns = [
    url(r'^productcatalog/', include('productcatalog.urls')),
    url(r'^admin/', include(admin.site.urls)),
]

来自app produtcatalog的我的urls.py

from django.conf.urls import url
from . import views


urlpatterns = [
    url(r'^$', views.index, name='index'),
    url(r'^productcatalog/$', views.catagory, name='catagory'),
    url(r'^productcatalog/$', views.manufacturer, name='brand'),
    url(r'^productcatalog/$', views.product, name='products'),
]

我确定错误发生在第二个urls.py文件中，但似乎无法捕获它。

Answer 1

我有另一种方法

urls.py from views import product urlpatterns=[url(r'^product/$', product)]

views.py def product(request): view="""<html><head></head><body><p>something</p></body></html> """ return HttpResponse(view)

我不记得我是否使用了渲染方法，但在将变量放入html页面时非常有用

Answer 2

您正在为所有视图功能使用相同的网址。尝试更改它。

urlpatterns = [
url(r'^$', views.index, name='index'),
url(r'^productcatalog-1/$', views.catagory, name='catagory'),
url(r'^productcatalog-2/$', views.manufacturer, name='brand'),
url(r'^productcatalog-3/$', views.product, name='products'),

Django的观点1.8

2 个答案: