Question

我试图查找所有显示器及其坐标（宽度w，高度h，x原点/左上角x和y原点/左上角 - 大多数y）并且正在使用此代码，它在某些系统上运行良好。但在其他系统上，我得到错误和重复的条目。如果我测试监视器是镜像的话，我是否能够避免这些dupilcate / false监视器条目？如何测试它的镜像？

所以这是我的代码：

// start - get all monitor resolutions
var screen = XRRGetScreenResources(getXOpenDisplay(), getDefaultRootWindow(getXOpenDisplay()));

var noutputs = screen.noutput;

for (var i=noutputs-1; i>=0; i--) {
    var info = XRRGetOutputInfo(getXOpenDisplay(), screen, screen.outputs[i]);
    if (info.connection == RR_Connected) {
        var ncrtcs = info.ncrtc;
        for (var j=ncrtcs-1; j>=0; j--) {
            var crtc_info = XRRGetCrtcInfo(getXOpenDisplay(), screen, infoCrtcs[j]);
            console.info('screen #' + i + ' mon#' + j + ' details:', crtc_info.x, crtc_info.y, crtc_info.width, crtc_info.height);

            collMonInfos.push({
                x: crtc_info.x,
                y: crtc_info.y,
                w: crtc_info.width,
                h: crtc_info.height
            });

            XRRFreeCrtcInfo(crtc_info);
        }
    }
    XRRFreeOutputInfo(info);
}
XRRFreeScreenResources(screen);
console.info('JSON:', JSON.stringify(collMonInfos));
// end - get all monitor resolutions

然后将此输出到日志：

"screen #4 mon#0 details:" 0 0 0 0
"screen #3 mon#1 details:" 0 0 1920 1200
"screen #3 mon#0 details:" 1920 469 1366 768
"screen #2 mon#1 details:" 0 0 1920 1200
"screen #2 mon#0 details:" 1920 469 1366 768
"screen #1 mon#1 details:" 0 0 1920 1200
"screen #1 mon#0 details:" 1920 469 1366 768
"screen #0 mon#1 details:" 0 0 1920 1200
"screen #0 mon#0 details:" 1920 469 1366 768

这是JSON格式：

[{
    "x": 0,
    "y": 0,
    "w": 0,
    "h": 0
}, {
    "x": 0,
    "y": 0,
    "w": 1920,
    "h": 1200
}, {
    "x": 1920,
    "y": 469,
    "w": 1366,
    "h": 768
}, {
    "x": 0,
    "y": 0,
    "w": 1920,
    "h": 1200
}, {
    "x": 1920,
    "y": 469,
    "w": 1366,
    "h": 768
}, {
    "x": 0,
    "y": 0,
    "w": 1920,
    "h": 1200
}, {
    "x": 1920,
    "y": 469,
    "w": 1366,
    "h": 768
}, {
    "x": 0,
    "y": 0,
    "w": 1920,
    "h": 1200
}, {
    "x": 1920,
    "y": 469,
    "w": 1366,
    "h": 768
}]

我真的只有2台显示器，1920x1200和1366x768。为什么所有其他条目以及如何测试以避免（而不是根据重复或0 h / w过滤掉）？

Answer 1

您不必要地遍历每个输出，然后遍历每个监视器。所以你收到重复的条目。您不必为每个输出调用XRRGetOutputInfo，因为您需要的所有数据（监视器数量）都可以在XRRGetScreenResources返回的结构中找到。这是可行的C代码（至少对我而言）：

#include <stdio.h>
#include <stdlib.h>
#include <X11/Xlib.h>
#include <X11/extensions/Xrandr.h>

int main(void) {
    Display *d = XOpenDisplay(getenv("DISPLAY"));
    Window   w = DefaultRootWindow(d);
    XRRScreenResources *xrrr = XRRGetScreenResources(d, w);
    XRRCrtcInfo *xrrci;
    int i;
    int ncrtc = xrrr->ncrtc;
    for (i = 0; i < ncrtc; ++i) {
        xrrci = XRRGetCrtcInfo(d, xrrr, xrrr->crtcs[i]);
        printf("%dx%d+%d+%d\n", xrrci->width, xrrci->height, xrrci->x, xrrci->y);
        XRRFreeCrtcInfo(xrrci);
    }
    XRRFreeScreenResources(xrrr);
    return 0;
}

Answer 2

接受的答案对我不起作用。我发现这样做的正确方法是：

#include <stdio.h>
#include <stdlib.h>
#include <X11/Xlib.h>
#include <X11/extensions/Xrandr.h>

int main(void) {
    Display *display = XOpenDisplay(NULL);

    if (NULL == display) {
        perror("No DISPLAY in environment!");
        exit(EXIT_FAILURE);
    }

    Window window = DefaultRootWindow(display);
    XRRScreenResources *screenr = XRRGetScreenResources(display, window);

    // This is the key right here. Use XRRScreenResources::noutput
    int output = screenr->noutput;

    for (int i = 0; i < output; ++i) {
        XRROutputInfo* out_info = XRRGetOutputInfo(display, screenr, screenr->outputs[i]);

        if (NULL != out_info && out_info->connection == RR_Connected) {
            XRRCrtcInfo* crt_info = XRRGetCrtcInfo(display, screenr, out_info->crtc);
            printf("%s\t%dx%d+%d+%d\n", out_info->name, 
                                        crt_info->width, 
                                        crt_info->height,
                                        crt_info->x,
                                        crt_info->y);
            XRRFreeCrtcInfo(crt_info);
        }

        XRRFreeOutputInfo(out_info);
    }

    XRRFreeScreenResources(screenr);
    XCloseDisplay(display);

    return 0;
}

正如我在代码注释中所说的那样，技巧是使用XRRScreenResources::noutput而不是XRRScreenResources::ncrtc

X11 - Xrandr给我假监视器

2 个答案: