Question

我正在编写查询以获取所有客户信息并显示他们上次订购的时间。我目前的疑问是：

SELECT
`user`.fname,
`user`.lname,
`user`.email,
`order`.orderplaced_ts,
COUNT(*) AS Total
FROM `order`
INNER JOIN `user` ON `order`.user_id = `user`.id
WHERE `order`.store_id = 10
AND `order`.orderplaced_ts > "2015-01-01 00:00:00"
AND `order`.order_status != "Cancelled"
GROUP BY `order`.user_id
ORDER BY `order`.orderplaced_ts

我在ORDER BY order.orderplaced_ts之后尝试了ASC和DESC，但仍然没有返回我想要的内容。

编辑：当前结果

First   Last         Email                  Date                  Count
Lisa    Day          email@something.com    2015-01-08 13:16:31    105
Alex    Sullivan     email@something.com    2015-01-05 11:48:33    90
Jill    GORDON       email@something.com    2015-01-02 12:52:57    68
Bob     Jain         email@something.com    2015-03-23 12:39:24    62
Jack    Merkher      email@something.com    2015-01-05 11:19:31    56

日期字段显示他们第一次订购，而我想要的是他们最后一次订购。

期望的结果将是：

    First   Last         Email                  Date                  Count
    Lisa    Day          email@something.com    2015-07-08 13:16:31    105
    Alex    Sullivan     email@something.com    2015-07-05 11:48:33    90
    Jill    GORDON       email@something.com    2015-07-02 12:52:57    68
    Bob     Jain         email@something.com    2015-07-23 12:39:24    62
    Jack    Merkher      email@something.com    2015-07-05 11:19:31    56

SELECT *的样本数据：

ID      User_ID Store_ID    orderplaced_ts
1104121 214831  10          2015-01-02 11:04:49
1104261 559281  10          2015-01-02 11:21:34
1104791 420461  10          2015-01-02 12:10:34
1105041 801481  10          2015-01-02 12:33:58
1105051 216501  10          2015-01-02 12:35:28
1105191 814661  10          2015-01-02 12:42:26
1105241 304571  10          2015-01-02 12:44:31
1105321 781611  10          2015-01-02 12:52:41
1105331 528411  10          2015-01-02 12:52:57
1105641 752171  10          2015-01-02 13:36:10
1106061 458791  10          2015-01-02 15:46:24

所以我要做的就是让所有用户，他们订购了多少次以及他们最近的订单是什么。

内部联接只是检索用户电子邮件，名字和姓氏。

解决问题的我的最终查询如下所示：

SELECT
    `user`.fname,
    `user`.lname,
    `user`.email,
    COUNT(*) AS Total_Orders,
    `order`.orderplaced_ts AS First_Order,
    MAX(order.orderplaced_ts) AS Last_Order
FROM `order`
INNER JOIN `user` ON `order`.user_id = `user`.id
WHERE `order`.store_id = 10
AND `order`.orderplaced_ts > "2015-01-01 00:00:00"
AND `order`.order_status != "Cancelled"
GROUP BY `order`.user_id ASC
ORDER BY `order`.orderplaced_ts

Answer 1

Group By子句中不包含的所有选定值必须具有sum或max等聚合函数。否则，分组选择将无法知道要显示的值。

我建议您按user.fname，user.lname和user.email而非order.user_id

对行进行分组

根据@Uueerdo的评论：按MAX(order.orderplaced_ts)排序可以解决问题

MYSQL内连接按升序DateTime排序

1 个答案: