Question

这是我的代码：

select column1, column2 from table1;

这是column1的预览：

1.1 Specimen Mislabeled
1.9 QNS- Specimen Spilled in transit
1.3 QNS-Quantity Not Sufficient
1.6 Test Requisition Missing
1.11 Other - Validity only
1.11 Other-reject per practice
1.5 Patient Info. entered Incorrectly
1.11 Other-Validity
1.11 Other-validity only
1.11 Other-Reject per agency
1.11 Other - not our req
1.11 Other - Not ML requisition
1.11 Other - Defective POC cups?

我希望它在1.11 Other

之类的内容时只返回"*1.11 Other*"

另外一句话我希望sql语句的结果是：

1.1 Specimen Mislabeled
1.9 QNS- Specimen Spilled in transit
1.3 QNS-Quantity Not Sufficient
1.6 Test Requisition Missing
1.11 Other
1.11 Other
1.5 Patient Info. entered Incorrectly
1.11 Other
1.11 Other
1.11 Other
1.11 Other
1.11 Other
1.11 Other

我该怎么做？

Answer 1

使用CASE声明;即。

SELECT 
  CASE WHEN Column1 LIKE '%1.11 Other%' 
     THEN '1.11 Other' 
     ELSE Column1 END AS Column1,
  Column2
FROM
   table1

Answer 2

select column1 from table1 where column1 like '1.11 Other*'

它可能是％而不是*我在sql和access之间混淆了。但我认为这是*。虽然如果这不起作用尝试％。基本上你在结尾使用通配符，所以匹配开头和从通配符开始的任何东西。

访问sql SELECT问题

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