下面显示的是我的表格，它显示产品和圈子作为复选框，我需要做的是存储在数据库中选中的复选框值。
1 #myform文件名= checkbox1.php
<!DOCTYPE html>
<!--
To change this license header, choose License Headers in Project Properties.
To change this template file, choose Tools | Templates
and open the template in the editor.
-->
<html>
<head>
<meta charset="UTF-8">
<title></title>
</head>
<body>
<form name="pdt_circle" method="GET" action="store.php">
<?php
$conn = mysqli_connect("localhost", "root", "", "demo");
if (mysqli_errno($conn)) {
echo 'database error' . mysqli_errno($conn);
} else {
$query = "select * from demo1";
$result = mysqli_query($conn, $query);
if ($result) {
echo '<table>';
echo '<tr><th>Select</th><th>Product</th><th>Circle</th></tr>';
while ($row = mysqli_fetch_assoc($result)) {
echo '<tr><td>';
echo "<input type=\"checkbox\" name=\"product[]\" id=\"product[]\" value=\"" . $row['Product'] . "\" ></td><td> " . $row['Product'];
echo '</td>';
echo '<td>';
echo "<input type=\"checkbox\" name=\"circle[]\" id=\"circle[]\" value=\"" . $row['Circle'] . "\" ></td><td>" . $row['Circle'];
echo '</td>';
echo '</tr>';
}
echo '</table>';
}
}
?>
<input type="submit" value="submit" name="sub" ><br>
</form>
</body>
</html>
我还创建了名为store.php的数据库文件。当我点击提交时，没有显示错误。但是数值不会存储在数据库中。
2＃store.php（数据库文件）
<?php
$conn = mysqli_connect("localhost", "root", "", "demo");
if (mysqli_errno($conn)) {
echo 'Database error';
} else {
echo 'i n else';
if (isset($_GET['circle']) and isset($_GET['product'])) {
if (is_array($_GET['circle']) and is_array('product')) {
$count = count($_GET['checkbox']);
foreach ($_GET['product'] as $pdt) { {
echo '';
$query1 = "insert into demo2 (Product) values ('$pdt')";
mysqli_query($conn, $query1);
}
foreach ($_GET['circle'] as $cir) { {
echo $cir;
$query = "insert into demo3 (Circle) values ('$cir')";
mysqli_query($conn, $query);
}
mysqli_close($conn);
}
}
}
}
}
?>
3＃sqlfiles写如下
--
-- Database: `demo`
--
-- --------------------------------------------------------
--
-- Table structure for table `demo1`
--
CREATE TABLE IF NOT EXISTS `demo1` (
`id` int(5) NOT NULL AUTO_INCREMENT,
`Product` varchar(25) NOT NULL,
`Circle` varchar(25) NOT NULL,
PRIMARY KEY (`id`),
UNIQUE KEY `id` (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=11 ;
--
-- Dumping data for table `demo1`
--
INSERT INTO `demo1` (`id`, `Product`, `Circle`) VALUES
(3, 'hello', 'surat'),
(4, 'callertune', 'ahmd'),
(5, 'hello', 'guj'),
(6, 'callertune', 'mp'),
(7, '3g', 'rajasthan'),
(8, 'data', 'mumbai'),
(9, 'callme', 'kolkata'),
(10, 'airtel_123', 'JK');
/*!40101 SET CHARACTER_SET_CLIENT=@OLD_CHARACTER_SET_CLIENT */;
/*!40101 SET CHARACTER_SET_RESULTS=@OLD_CHARACTER_SET_RESULTS */;
/*!40101 SET COLLATION_CONNECTION=@OLD_COLLATION_CONNECTION */;
SQL2：表名= DEMO2
--
-- Database: `demo`
--
-- --------------------------------------------------------
--
-- Table structure for table `demo2`
--
CREATE TABLE IF NOT EXISTS `demo2` (
`id` int(5) NOT NULL AUTO_INCREMENT,
`Product` varchar(25) NOT NULL,
PRIMARY KEY (`id`),
UNIQUE KEY `id` (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=1 ;
/*!40101 SET CHARACTER_SET_CLIENT=@OLD_CHARACTER_SET_CLIENT */;
/*!40101 SET CHARACTER_SET_RESULTS=@OLD_CHARACTER_SET_RESULTS */;
/*!40101 SET COLLATION_CONNECTION=@OLD_COLLATION_CONNECTION */;
3＃表名：demo3
--
-- Database: `demo`
--
-- --------------------------------------------------------
--
-- Table structure for table `demo3`
--
CREATE TABLE IF NOT EXISTS `demo3` (
`id` int(5) NOT NULL AUTO_INCREMENT,
`Circle` varchar(25) NOT NULL,
PRIMARY KEY (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=1 ;
/*!40101 SET CHARACTER_SET_CLIENT=@OLD_CHARACTER_SET_CLIENT */;
/*!40101 SET CHARACTER_SET_RESULTS=@OLD_CHARACTER_SET_RESULTS */;
/*!40101 SET COLLATION_CONNECTION=@OLD_COLLATION_CONNECTION */;
表单形式的链接： https://drive.google.com/file/d/0B1rpCWtUcfePM3hVZEpHLXByeW8/view?usp=sharing
答案 0 :(得分：0)
一些指示：
checkbox1.php ＆lt; - 包含多个id =＆＃34; circle []＆＃34;这是无效的（但不会导致您的问题）。
另外，为什么不使用POST而不是GET？
<强> store.php 调试时，请始终显示已发布的数据，以便检查您正在处理的内容，如下所示：
echo "<pre>";
print_r($_GET);
echo "<pre>";
exit;
删除此项检查：
if (is_array($_GET['circle']) and is_array('product')) {
你知道它何时被设置，那必须是一个数组。
另外，我认为你并不想检查产品是否＆＃39;是一个数组。我希望您想查看$ _GET [＆＃39;产品＆＃39;]。
请看下面的代码，稍微清理一下：
$conn = mysqli_connect("localhost", "root", "", "demo");
if (mysqli_errno($conn)) {
echo 'Database error';
} else {
$postedCircles = (isset($_GET['circle']))?$_GET['circle']:array();
$postedProducts = (isset($_GET['product']))?$_GET['product']:array();
foreach ($postedCircles as $cir) {
// You are totally vuerable to SQL injection here, don't do it like this
$query = "insert into demo3 (Circle) values ('".$cir."')";
echo $query;
mysqli_query($conn, $query);
}
foreach ($postedProducts as $pdt) {
// You are totally vuerable to SQL injection here, don't do it like this
$query = "insert into demo2 (Product) values ('".$pdt."')";
echo $query;
mysqli_query($conn, $query);
}
mysqli_close($conn);
}
它产生什么输出？ 那是法律问题吗？你能用手对mysql运行吗？
最后，请不要在查询中使用来自客户端的原始值。 以这种方式插入不需要的SQL非常容易（查找：SQL注入）